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boyakko [2]
3 years ago
9

20 sixth graders were asked: How many potted plants are in your home. Draw a histogram to represent the data, which is shown bel

ow. 0,1,2,2,3,4,4,5,5,6,6,6,6,7,7,8,8,9,11,12

Mathematics
1 answer:
ELEN [110]3 years ago
8 0

Answer:

The histogram is attached below.

Step-by-step explanation:

The data for the number of potted plants every 20 sixth grader has in their home is:

S = {0, 1, 2, 2, 3, 4, 4, 5, 5, 6, 6, 6, 6, 7, 7, 8, 8, 9, 11, 12}

Form the frequency distribution of the data as follows:

               <em>X</em> : 0   1  2   3  4  5  6  7  8  9  10  11  12

<em>Frequency</em>:  1    1   2   1   2   2   4   2   2   1    0    1     1

The histogram is attached below.

The mode of the data is, 6.

Since it has the highest frequency.

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Step-by-step explanation:

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The probability that all 5 selected workers will be from the day shift is,

\begin{array}{c}\\P\left( {{\rm{all \ 4 \  selected   \ workers\  will \  be  \ from  \ the \  day \  shift}}} \right) = \frac{{\left( \begin{array}{l}\\10\\\\4\\\end{array} \right)}}{{\left( \begin{array}{l}\\24\\\\4\\\end{array} \right)}}\\\\ = \frac{{210}}{{10626}}\\\\ = 0.0198\\\end{array}

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P( all 4 selected workers will be) = \dfrac{ (^{10}_4) }{(^{24}_4)}+\dfrac{ (^{8}_4) }{(^{24}_4)} + \dfrac{ (^{6}_4) }{(^{24}_4)}

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(^{8}_4) } = \dfrac{8!}{4!(8-4)!} = 70

(^{6}_4) } = \dfrac{6!}{4!(6-4)!} = 15

∴ P( all 4 selected workers is ) =\dfrac{210+70+15}{10626}

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P ( at least two different shifts will be represented among the selected workers)  = 1-\dfrac{ (^{10}_4) }{(^{24}_4)}+\dfrac{ (^{8}_4) }{(^{24}_4)} + \dfrac{ (^{6}_4) }{(^{24}_4)}

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