How do i graph 2.5x+8y=200
1 answer:
Answer:
Step-by-step explanation:
2.5x+8y=200
We want to get this in slope intercept form so we will solve for y
Subtract 2.5x from each side
2.5x-2.5x+8y=-2.5x +200
8y = -2.5x +200
Now divide by 8 on both sides
8y/8 = -2.5x/8 + 200/8
y = -.3125x +25
The y intercept is 25, so plot a point there
-.3125 = -5/16
Go down 5 and to the right 16 and plot a point. Connect the two points to make a line.
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Draw dagarm (see attachment)
we've got a right triangle
the legs are 12 and 15
and the hypohuse is the diagonal
remember, for any right tirnalge
when the legs are a and b and hytponuse is c then
a²+b²=c²
so
12²+15²=c²
144+225=c²
369=c²
sqrt both sides
√369=c
3√41=c
the diagonal is 3√41 m or about 19.2m
we've got a right triangle
the legs are 12 and 15
and the hypohuse is the diagonal
remember, for any right tirnalge
when the legs are a and b and hytponuse is c then
a²+b²=c²
so
12²+15²=c²
144+225=c²
369=c²
sqrt both sides
√369=c
3√41=c
the diagonal is 3√41 m or about 19.2m