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Goryan [66]
3 years ago
11

Denise is using a ladder to clean the outside of her second story windows. The ladder she is using is 24 feet long, and she puts

the base of the ladder 13 feet away from the house in order to avoid her flower gardens. How high up the side of her house does the ladder reach?
Mathematics
1 answer:
agasfer [191]3 years ago
3 0
In order to solve this you have to use the pythagorean’s theorem, which is a^2+b^2=c^2. from the problem you can find out you have a=13ft and c=24ft. c is your hypotenuse. you then solve and you get b=20.17ft. you can check to make sure the answer is right, but that is how you solve it. And the ladder would reach 20.17ft.
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How would you solve this? help.
Eddi Din [679]

Answer:

<em>Center: (3,3)</em>

<em>Radius: </em>2\sqrt{5}<em />

Step-by-step explanation:

<u>Midpoint and Distance Between two Points</u>

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

\displaystyle x_m=\frac{x_1+x_2}{2}

\displaystyle y_m=\frac{y_1+y_2}{2}

The distance between both points is given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3

\displaystyle y_m=\frac{7-1}{2}=\frac{6}{2}=3

Center of circle C: (3,3)

The radius of C is half the distance between A and B:

d=\sqrt{(1-5)^2+(-1-7)^2}

d=\sqrt{16+64}=\sqrt{80}=\sqrt{16*5}=4\sqrt{5}

The radius of C is d/2:

r =4\sqrt{5}/2 = 2\sqrt{5}

Center: (3,3)

Radius: 2\sqrt{5}

8 0
3 years ago
A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the im
loris [4]

Answer:

Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).

As, DO is Dilation of Δ ABC by Scale factor of \frac{1}{2}.

Vertices of A' B'C' are

A'=(\frac{-4}{2},\frac{3}{2})=(-2,\frac{3}{2}), B'=(\frac{4}{2},\frac{4}{2})=(2,2), C'=(\frac{1}{2},\frac{1}{2})

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.

The two triangles will be congruent.

AO is Dilated by a factor of half , so A'O' will be half of AO.

So, correct Statements are

1. AB is parallel to A'B'.

2.DO,1/2(x, y) =  

The distance from A' to the origin is half the distance from A to the origin.

OA=\sqrt{(-4)^2+3^2}=\sqrt{25}=5\\\\ O'A'=\sqrt{2^2+(\frac{3}{2})^2}=\frac{5}{2}=2.5

8 0
3 years ago
Read 2 more answers
A rectangular pool is 18 meters wide and 24 meters long. If you swim diagonally across the pool, how many meters would you be sw
Zanzabum
Using the Pythagorean theorem, the diagonal measure is found as
  √((18 m)² +(24 m)²) = √(324 +576) m = √900 m
  = 30 m

You would be swimming 30 meters.
6 0
3 years ago
Mya wants to create a rectangular garden that will be 25 feet wide. She has 110 feet of
jok3333 [9.3K]

750 sq ft

Step-by-step explanation:

since the fencing is going around the perimeter, you have to have two sides with the width of 25 feet, you would use 50 feet of fencing for 2 of the sides. You will have 60 feet of fencing left, divided by 2 (length of the garden) = 30 feet long.

The area (length x width) or (25 x 30) = 750 sq ft of garden space. Draw a rectangle with 25 ft on two parallel sides and 30 ft on the other two sides and show these equation= 25 x 2= 50, 110 - 50 = 60

60 ÷ 2 = 30, 30 x 25 = 750

7 0
3 years ago
-9y+7=24y-4. Solve for y.
patriot [66]

Answer:

y=1/3

Step-by-step explanation:

-9+7=24y-4

7=33y-4

11=33y

y=1/3

6 0
3 years ago
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