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2 years ago

The volume of a gas in cubic centimeters, V, varies inversely with the

Mathematics

1 answer:

Nina [5.8K]2 years ago

6 0

Answer:

C. 128 cm³

Step-by-step explanation:

16(20) = 320

320/2.5 = 128 cm³

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If line t is perpendicular to both line l and line m, then ?1 and ?2 are both ____ angles.

marusya05 [52]

Answer:

Step-by-step explanation

Botch are right angles

4 0

3 years ago

Q7. Average of 60 numbers are 55. When 10 more numbers are included, the average of

Nikitich [7]

Answer:

The average of the 10 numbers is 195

Step-by-step explanation:

The average of a set of numbers is the sum of the numbers dividing by their number

Average = The sum ÷ The number

∵ The average of 60 numbers is 55

∴ The average = 55

∴ The number = 60

→ Substitute them in the rule above to find the sum of the numbers

∵ 55 = The sum ÷ 60

→ Multiply each side by 60

∴ 3300 = The sum

∴ The sum of the 60 numbers = 3300

∵ 10 more numbers are included

∵ The average of 70 numbers become 75

∴ The average = 75

∴ The number = 70

→ Substitute them in the rule above to find the sum of the numbers

∵ 75 = The sum ÷ 70

→ Multiply each side by 70

∴ 5250 = The sum

∴ The sum of the 70 numbers = 5250

∵ The sum of the 10 numbers that added is the difference between

the sums of the 60 and 70 numbers

∵ The difference between the sums = 5250 - 3300

∴ The difference between the sums = 1950

→ To find the average of them divide their sum by 10

∵ The average of the 10 numbers = 1950 ÷ 10

∴ The average of the 10 numbers = 195

5 0

3 years ago

Which equation can be used to find the area of the rectangle? A. A=9+4 B. A=1/2 (9)(4) C. A=9+9+4+4 D. A=(9)(4)

valentina_108 [34]

Answer:

D. A=(9)(4)

Step-by-step explanation:

area= length x width = 9x4

6 0

3 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

Read 2 more answers

A 50-foot ladder leans against a building. If the base of the ladder is 6 feet from the base of the building, what is the angle

adell [148]

Answer:

The angle between the building and the ladder $\theta =$ 6.9°