If two dices are rolled once, you would have a total number of 6*6=36 possibilities.
To get a sum greater than 10:
A) one of your dices could be showing a 5, the other a 6. That’s two possibilities. Dice A being the 5 or dice B being the 5.
B) both of your dices could be showing 6s.
That’s one possibility.
So your overall possibility to get a sum greater than 10 is (1+2)/36 3/36=1/12
One twelfth.
Answer:
z = -5
Step-by-step explanation:
3(0.7z + 2.8) = 7(1.5z + 7.2)
2.1z + 8.4 = 10.5z + 50.4
2.1z - 10.5z = 50.4 - 8.4
-8.4z = 42
z = 42/(-8.4)
z = -5
Answer:
42.64°
Step-by-step explanation:
Note: A rhombus has all its sides equal, its opposite angle are equal, its has bigger and smaller diagonal, diagonal bisect the angles and diagonal bisect each other.
From the diagram attached,
sinθ = opposite/adjacent
sinθ = 4/11
θ = sin⁻¹(4/11)
θ = 21.32
Therefore, from the diagram,
The smaller angle of the rhombus = 2θ
The smaller angle of the rhombus = (2×21.32)
The smaller angle of the rhombus = 42.64°
<span>So we need to see how does the decimal point change it's place in the quotient when we divide any number by increasing powers of 10. Lets start with number 1. The decimal point is: 1.0 and when we divide by 10^1=10 we get 1/10=0.1. The decimal point has moved one place to the left. Now lets divide 1 by 10^2 and we get 1/100=0.01. Again, the decimal point has moved one more place to the left. Now: 1/10^3 = 1/1000 = 0.001. Next would be 0.0001, next one would be 0.00001 and so on. </span>
