Answer:
look up answer key realy would help
Step-by-step explanation:
Answer:
So we already knew all three sides, there are more than one way to do it, for example:
sin∠F = HG/HF = 12/13
cos∠F = GF/HF = 5/13
tan∠F = HG/GF = 12/5
ctg∠F = GF/HG = 5/12
All of them will give you the result which is approximately 67°.
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
The answer is C. 50%
Step-by-step explanation:
I'm doing the same thing and it's right. Trust me:)