To rewrite something as a decimal, simply divide the numerator and denominator.
-33 / 25 = -1.32
So -33/25 = -1.32
Answer:
I'm pretty sure it's 21 11/12. Don't get mad if I'm wrong
Step-by-step explanation:
-7 2/3 - 5 1/2 + 8 3/4
= -7 8/12 - 5 6/12 + 8 9/12
12 14/12 + 8 9/12
20 23/12
= 21 11/12
Answer: Manager has evidence that the filling machine is over dash filling the cans.
Step-by-step explanation:
Let 
be the average amount of fluid per can.
Given claim : A can of soda is labeled as containing 15 fluid ounces.
i.e. 
The quality control manager wants to verify that the filling machine is not over dash filling the cans.
i.e. 
Since null hypothesis always contains equals sign.
So, the set of hypothesis for the given situation will be :-
Also, the quality control manager obtains a sample of 78 cans and measures the contents.
The sample evidence leads the manager to reject the null hypothesis.
That means he has evidence that the filling machine is over dash filling the cans.
Answer:
Slope = 6.25
Y-intercept = 8.50 or 8.5
Equation: y = 6.25x + 8.50 or y = 6.25x + 8.5
Proportional = No
Step-by-step explanation:
The slope is also the rate of change and the question states that Kayla earned $6.25 an hour. So your slope also known as rate of change is 6.25.
Your y-intercept is the starting point and in the question it states that Kayla received $8.50 in tips. So your y-intercept also known as starting point is $8.50.
The Equation is meant to be set-up like this:
y = mx + b which is y = slope + y-intercept
Since $6.25 is our slope and $8.50 is our y-intercept lets arrange it:
y = 6.25x + 8.50
A proportional graph is a graph that has the line drawn from the equation going through the origin which is (0,0) the middle intersection between the y and x line. So with that being said the graph is not proportional because it doesn't go through the origin.
How do I know this?
I know this because the starting point in the equation that I graph is 8.50 or 8.5 and it does not start from (0,0) or 0 so it does not cross the (0,0) point.
Answer:
4.45 ccs will remain after 5 hours.
Step-by-step explanation:
The anti-biotic in his body decreases at a rate proportional to the amount, Q(t), present at time t.
(dQ/dt) = - kQ ((Minus sign because it's a rate of reduction)
(dQ/dt) = -kQ
(dQ/Q) = -kdt
∫ (dQ/Q) = -k ∫ dt
Solving the two sides as definite integrals by integrating the left hand side from Q₀ to Q and the Right hand side from 0 to t.
We obtain
In (Q/Q₀) = -kt
(Q/Q₀) = e⁻ᵏᵗ
Q(t) = Q₀ e⁻ᵏᵗ
the initial injection was 8 ccs and 5 ccs remain after 4 hours
Q₀ = 8 ccs,
At t = 4 hours, Q = 5 ccs
5 = 8 e⁻ᵏᵗ
e⁻ᵏᵗ = 0.625
-kt = In (0.625) = -0.47
-4k = 0.47
k = 0.1175 /hour
Q(t) = Q₀ e⁻⁰•¹¹⁷⁵ᵗ
At t = 5 hours, Q = ?
Q = 8 e⁻⁰•¹¹⁷⁵ᵗ
0.1175 × 5 = 0.5875
Q = 8 e(^-0.5875)
Q = 4.45 ccs
Hope this Helps!!!
