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____ [38]
3 years ago
13

A can of soda is labeled as containing 15 fluid ounces. The quality control manager wants to verify that the filling machine is

not over dash filling the cans. Complete parts​ (a) through​ (d) below. ​(a) Determine the null and alternative hypotheses that would be used to determine if the filling machine is calibrated correctly. Upper H 0​: mu equals 15 Upper H 1​: mu greater than 15 ​(Type integers or decimals. Do not​ round.) ​(b) The quality control manager obtains a sample of 78 cans and measures the contents. The sample evidence leads the manager to reject the null hypothesis. Write a conclusion for this hypothesis test.
Mathematics
1 answer:
dedylja [7]3 years ago
7 0

Answer: Manager has evidence that the filling machine is over dash filling the cans.

Step-by-step explanation:

Let \mu be the average amount of fluid per can.

Given claim : A can of soda is labeled as containing 15 fluid ounces.

i.e. \mu=15

The quality control manager wants to verify that the filling machine is not over dash filling the cans.

i.e.  \mu>15

Since null hypothesis always contains equals sign.

So, the set of hypothesis for the given situation will be :-

H_0:\mu=15\\\\H_a:\mu>15

Also, the quality control manager obtains a sample of 78 cans and measures the contents.

The sample evidence leads the manager to reject the null hypothesis.

That means he has evidence that the filling machine is over dash filling the cans.

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stiv31 [10]

Answer:

d ≈ 87.85 yards

Step-by-step explanation:

The circumference ( C) of a circle is calculated as

C = πd ( d is the diameter ), then

276 = πd ( divide both sides by π )

\frac{276}{\pi } = d , so

d ≈ 87.85 yards ( to the nearest hundredth )

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3 years ago
Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

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C

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Answer:
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So, if the geometric mean of 3 and a is 9 =>

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=> 9^2 = 3a

=> a = 9^2 / 3

a = 81 / 3

a = 27

Answer: the value of a is 27.
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