The correct answer for the question that is being presented above is this one: "5.5" <span>Keeping in mind the role the order of precedence plays in equations, Excel would display as the result of the following equation? =(24+75)/(6*3): 5.5.</span>
Answer:
Arbisoft is listed as the top cpmpany.
Explanation:
The top 5 are:
Arbisoft
Cygnis Media
Tintash
Square63
OneByte
Answer:
Answer is:
Client-Server Network
- expensive to set up
- has a central server
- easy to track files
- useful for a large organization
Peer-to-peer Network
- useful for a small organization
- difficult to track files
- inexpensive to set up
- does not have a central server
Explanation:
<em>Client-Server Network is ideal for bigger network set up like offices and companies where there will be a central server involved with several clients to access and connected with the server. This is the normal network set up to companies. While, Peer to peer network is ideal for much smaller network, which consists of only two computers to communicate and share files. This network is normally temporary and inexpensive since in only works with two computers.</em>
Answer:
See explaination
Explanation:
java code:
class DONALD
{
static class Node
{
int data;
Node next;
}
static Node head=null;
static int largestElement(Node head)
{
Int max=Integer.MIN_VALUE;
while(head!=null)
{
if(max<head.data)
max=head.data;
head=head.next;
}
return max;
}
static int smallestElement(Node head)
{
int min=Integer.MAX_VALUE;
while(head!=null)
{
if(min>head.data)
min=head.data;
head=head.next;
}
return min;
}
static void push(int data)
{
Node newNode=new Node();
newNode.data= data;
newNode.next=(head);
(head)=newNode;
}
static void printList(Node head)
{
while(head!=null)
{
System.out.println(head.data + " -> ");
head=head.next;
}
System.out.println("NULL");
}
public static void main(String[] args)
push(15);
push(14);
push(13);
push(22);
push(17);
System.out.println("Linked list is : ");
printList(head);
System.out.println("Maximum element in linked list: ");
System.out.println(largestelement(head));
System.out.print("Maximum element in Linked List: " );
System.out.print(smallestElement(head));
}
}
