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coldgirl [10]
3 years ago
8

Ben uses a table that has few columns. He knows about a particular value in the first column and wants to find the corresponding

value of the row. What data organization technique can Ben use?
Computers and Technology
2 answers:
erastovalidia [21]3 years ago
8 0

on plato the answer is lookup function

igor_vitrenko [27]3 years ago
4 0
I'd suggest he uses LOOKUP Function.

You can use the LOOKUP function when you need to look in a single column or row and find a value from the same position in a corresponding column or row. We have a much improved VLOOKUP that can also be used to search one row or column or multiple rows and columns.



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Create two classes. The first, named Sale, holds data for a sales transaction. Its private data members include the day of the m
olya-2409 [2.1K]

Answer:

A C++ program was used in creating two classes. the code is stated below.

Explanation:

Solution

The C++ program is executed below:

#include<iostream>

using namespace std;

//declare class (will be define later)

class Salesperson;

//class Sale

class Sale

{

  //private members of class

  private:

      string day;

      double amtOfSale;

      int salesPersonId;

 //public methods

  public:

      //constructor that takes day,amount of sale and salesPersonId as parameters

      Sale(string date,double sale,int id)

      {

          //set the private members to the initial values passed

          day=date;

          amtOfSale=sale;

          salesPersonId=id;

      }    

      //declare a friend function that takes objects of the two classes as parameters

      friend void display(Sale,Salesperson);

};  

//define class Salesperson

class Salesperson

{

  //private members of the class

  private:

      int salesPersonId;

      string lastName;    

  //public methods

  public:

      //constructor that takes name and id as parameters

      Salesperson(int id,string name)

      {

          //set the members of the class with the parameters passed

          salesPersonId=id;

          lastName=name;

      }  

      //declare a friend function that takes objects of the two classes as parameters

      friend void display(Sale,Salesperson);

};

//define the friend funtion

void display(Sale saleObj,Salesperson personObj)

{

  //display the sales info using the objects of the two classes

  cout<<"\nSale #"<<saleObj.salesPersonId<<" on "<<saleObj.day<<" for $"<<saleObj.amtOfSale<<" sold by #"<<personObj.salesPersonId<<" "<<personObj.lastName;

}  

int main()

{

  //create object for Sale class and pass default values

  Sale sObj1("12/25/2016",559.95,103);

  //create object for Salesperson class and pass default values

  Salesperson pObj1(103,"Woods");

 

  //create another object for Sale class and pass default values

  Sale sObj2("11/15/2016",359.95,106);

  //create another object for Salesperson class and pass default values

  Salesperson pObj2(106,"Hansen");

  //using the friend function dislay the sales info

  display(sObj1,pObj1);

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  return 0;

}

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mixer [17]

Answer:

   public static double convertToInches(double numFeet, double numInches){

       return (numFeet*12)+numInches;

   }

Explanation:

This technique of having more than one method/function having the same name but with different parameter list is called method overloading. When the method is called, the compiler differentiates between them by the supplied parameters. The complete program is given below

public class FunctionOverloadToInches {

   public static void main(String[] args) {

       double totInches = 0.0;

       totInches = convertToInches(4.0, 6.0);

       System.out.println("4.0, 6.0 yields " + totInches);

       totInches = convertToInches(5.9);

       System.out.println("5.9 yields " + totInches);

       return;

   }

   public static double convertToInches(double numFeet)

       {

           return numFeet * 12.0;

       }

       /* Your solution goes here */

   public static double convertToInches(double numFeet, double numInches){

       return (numFeet*12)+numInches;

   }

}

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3 years ago
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