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3 years ago

Find all the real square roots of 0.0004.

Mathematics

2 answers:

Julli [10]3 years ago

8 0

The correct answer will be 0.02 Square root

chubhunter [2.5K]3 years ago

5 0

Hey!!

the answer is 0.02 !.

if helped, brainliest

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The volume of a cube is 1, 953.125 centimeters cubed. Find the length of the sides. Round to the nearest tenth.

Shtirlitz [24]

1953.13 is the length of the sided

6 0

3 years ago

Write an equation in slope intercept form that passes through the point (3,9) and has a slope of -5

Anna35 [415]

Answer:

y= -5x +24

Step-by-step explanation:

Slope-intercept form

y= mx +c, where m is the slope and c is the y-intercept.

Given that the slope is -5, m= -5.

Substitute m= -5 into the equation:

y= -5x +c

To find the value of c, substitute a pair of coordinates that the line passes through into the equation:

When x= 3, y= 9,

9= -5(3) +c

9= -15 +c

c= 9 +15

c= 24

Thus, the equation of the line is y= -5x +24.

5 0

2 years ago

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m

Harrizon [31]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

Let $\mu$ = average mg of mercury in compact fluorescent bulbs.

So, Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean mg of mercury = 3.59

$\sigma$ = population standard deviation = 0.18 mg

n = sample of bulbs = 25

So, test statistics = $\frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }$

= 2.50

The value of z test statistics is 2.50.

Now, P-value of the test statistics is given by;

P-value = P(Z > 2.50) = 1 - P(Z $\leq$ 2.50)

= 1 - 0.9938 = 0.0062

Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0

3 years ago

The expression n2 + n represents the total number of blocks used in the nth figure of a pattern. Use the equation n2 + n = 56 to

Brrunno [24]

We have to solve this quadratic equation $n^{2}+n=56$ for n to get which figure has 56 blocks.