Answer:
a 40, aka a failing grade ( do ur test :) )
Step-by-step explanation:
Start at one of the vertices and draw a line from there to a point on the oposite side, not ending at another vertex

- the current possible number of plates
after adding 2 letters into the 1st set:

after adding 2 letters into the 2nd set:

after adding 2 letters into the 3rd set:

after adding 1 letter into the 1st set and 1 into the 2nd set:
after adding 1 letter into the 1st set and 1 into the 3rd set:
after adding 1 letter into the 2nd set and 1 into the 3rd set:
<span>The largest possible number of plates after adding two numbers is 100.
So, </span><span>the largest possible number of additional plates is 100-60=
40</span>
Answer:
N(20) = T
Step-by-step explanation:
N = Amount of lawns
20 = payment per lawn
T= payment after N lawns
Lets say there were 2 lawns
2(20)=T
40$ for 2 lawns
In exact form it is 13/6 .. and mixed numbers it is 2 1/6