Please help me with this.

Digiron [165]

Answer: £164.50 i think soooo

4 0

3 years ago

The Municipal Transit Authority wants to know if, on weekdays, more passengers ride the northbound blue line train towards the c

Kitty [74]

Answer:

The 90% confidence interval $-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

The distribution test statistics is $t = -3.222$

The rejection region is p-value < $\alpha$

The decision rule is reject the null hypothesis

The conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

The p-value is $p-value =0.000951$

Step-by-step explanation:

From the question we are told that

The first sample size $n_1 = 30$

The first sample mean is $\= x _1 = 323$

The first standard deviation is $s_1 = 41$

The second sample size is $n_2 = 45$

The second sample mean is $\=x_2 = 356$

The second standard deviation is $s_2 = 45$

given that the confidence level is 90% then the level of significance is mathematically represented as

$\alpha = (100 -90)\%$

$\alpha = 0.10$

Generally the critical value of $\frac{\alpha }{2}$ obtained from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the pooled variance is mathematically represented as

$s^2 = \frac{(n_1 - 1)s_1^2 + (n_2 -1)s_2^2 }{n_1 + n_2 -2}$

$s^2 = \frac{(30 -1)(41^2) + (45-1)45^2}{30+45 -2}$

$s^2 = 1888.34$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s^2}{n_1} + \frac{s^2}{n_2} }$

=> $SE = \sqrt{\frac{1888.34}{30} + \frac{1888.34}{45} }$

=> $SE = 10.24$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * SE$

$E = 1.645* 10.24$

$E = 16.85$

Generally the 90% confidence interval is mathematically represented as

$\=x_1 -\=x_2 -E < \mu_1 -\mu_2 < \=x_1 -\=x_2 +E$

$323 -356 -16.84$

$-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \=x_2 }{SE}$

=> $t = \frac{323-356}{10.24}$

=> $t = -3.222$

Generally the degree of freedom is mathematically represented as

$df = n_1+n_2 -2$

$df = 30 + 45 -2$

$df = 73$

The p-value is obtained from the student t distribution table at degree of freedom of 73 at 0.05 level of significance

The value is $p-value =0.000951$

Here the level of significance is $\alpha = 5\% = 0.05$

Given that the p-value < $\alpha$ then we reject the null hypothesis

Then the conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

5 0

3 years ago

PLEASE ANSWER + BRAINLIEST !!!!<br><br> Find the indicated sum for the arithmetic series.

schepotkina [342]

Hello there,

I believe the answer would be 17×6 - 6(9+14)(6)/2 = 102 -414 = -312 but i am not 100% Sure!! Sorry if I am wrong!

Hope I helped

8 0

3 years ago

Which table of ordered pairs represents a proportional relationship?

dedylja [7]

Answer:

A 2-column table with 3 rows. Column 1 is labeled x with entries 14, 28, 42. Column 2 is labeled y with entries 2, 4, 6.

Step-by-step explanation:

Examining the response options:

A 2- compartment chart with 3 rows. Column 1 is designated x with records 1, 5, 6. compartment 2 is designated y with records 5, 20, 30.

No, as y = 25 not 20 and x = 5 .

A 2- compartment chart with 3 rows. Column 1 is identified x with approaches 48, 32, 16. compartment 2 is designated y with listings 4, 2, 1.

No, y =64 not 48 and x= 4.

A 2- compartment chart with 3 lines. compartment 1 is designated x with records 0, 1, 3. compartment 2 is designated y with records 90, 70, 25.

No, y= 25+3*45= 160 not 90 and x = 3.

A 2- compartment chart with 3 lines. compartment 1 is designated x with records 42, 28, 14. compartment 2 is designated y with records 2, 4, 6.

Yes, as 2*7 = 14, 4*7= 28, 6*7= 42.

5 0

3 years ago

Read 2 more answers

If a bus travels at 48MPH how long will it take to be able to travel 60 miles

GrogVix [38]

It will take 1.25 hours

8 0

3 years ago