There are 20 possible combinations I believe.
Problem 7: Correct
Problem 8: Correct
Problem 9: Correct
The steps are below if you are curious
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Problem 7
S = 180*(n-2)
2340 = 180*(n-2)
2340/180 = n-2
13 = n-2
n-2 = 13
n = 13+2
n = 15
I'm using n in place of lowercase s, but the idea is the same. If anything, it is better to use n for the number of sides since S already stands for the sum of the interior angles. I'm not sure why your teacher decided to swap things like that.
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Problem 8
First find y
y+116 = 180
y+116-116 = 180-116
y = 64
which is then used to find x. The quadrilateral angles add up to 180*(n-2) = 180*(4-2) = 360 degrees
Add up the 4 angles, set the sum equal to 360, solve for x
x+y+125+72 = 360
x+64+125+72 = 360 ... substitution (plug in y = 64)
x+261 = 360
x+261-261 = 360-261
x = 99
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Problem 9
With any polygon, the sum of the exterior angles is always 360 degrees
The first two exterior angles add to 264. The missing exterior angle is x
x+264 = 360
x+264-264 = 360-264
x = 96
Answer:
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Answer:
32.04% to 2 decimal places.
Step-by-step explanation:
As a fraction it is 17.3 / 54
To get the percentage we multiply by 100:
= (17.3/54) * 100
= 32.04%
Answer:
m(C)<m(B)<m(A).
Step-by-step explanation:
1) according to the condition the shortest side is AB, the longest side is BC, the middle is AC. Then
2) the smallest angle is BCA (or C), the middle angle is ABC (or B), the largest angle is BAC (or A).
