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bezimeni [28]
3 years ago
8

During its first year, there were 138 volunteers at a community outreach program. Over the next 2 years, there were 156 voluntee

rs and 175 volunteers, respectively. What is the percent of increase in volunteers from Year 1 to Year 2 and from Year 1 to Year 3? Round to the nearest tenth percent if necessary.
Mathematics
1 answer:
dem82 [27]3 years ago
5 0

Answer:

0.1%

Step-by-step explanation:

138 into a percent=1.38%

156 into a percent=1.56%

175 into a percent=1.75%

1.38-1.56=0.18

1.56-1.75=0.19

0.19-0.18= <u>0.1%</u>

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Quadrilateral ABCD is the result of a translation of quadrilateral EFGH. Segment EF is parallel to segment HG in the pre-image.
Mazyrski [523]
The correct answer:
The corresponding segments BC and AD in the image are parallel
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Identify whether the function graphed has an odd or even degree and a positive or negative leading coefficient.
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A line m is perpendicular to an angle bisector of ∠A. The sides of ∠A intersect this line m at points M and N. Prove that △AMN i
Ray Of Light [21]

Answer:


Step-by-step explanation:

<em><u>Given</u></em><u>:</u>       A line m is perpendicular to the angle bisector of ∠A. We call this  

                 intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.

                 AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.

<u><em>To Prove</em></u>:   <em><u>ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are</u></em>

<em>                    </em><em><u>equal. </u></em>

<em><u>Solution</u></em>:  Now, In ΔADM and ΔADN

                 ∠MAD=∠NAD     ...(1) (∵Given)

                  AD=AD                ...(2) (∵common side)

                  ∠ADM=∠ADN     ...(3) (∵Given)

                  <u><em> Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN</em></u>

                                                         ( ∵ ASA  congruence rule)

                  ⇒<u><em> AM=AN</em></u>

                  Now, In Δ AMN

                 AM=AN (∵ Proved)

                  Hence, ΔAMN is an isosceles  triangle.


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Diano4ka-milaya [45]

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