Answer: z(e) = 2.07
Step-by-step explanation:
1.-The problem is about a test of proportions. As research company claims than no more 55 % of Americans regularly watch Fox News
The null hypothesis is H₀ P₀ ≤ 0.55 from 55%
And the alternative hypothesis is Hₐ Pₐ > .55
Is one tail test
2.-We have to specify significance level we assume our test will be for a significance level α = 5% or α = 0,05
3.-Calculation of z (c) = ?? and z (e) = '??
For z (c) we find in z table the value of z(c) = 1.64
For z (e) = ( P -P₀)/√p₀q₀/n z(e) = 0.05 / √(0.55*0,45)/425 z(e) = 0,05/ 0.02413 z(e) = 2.07
z(e) > z(c) threfore z(e) is in the rejection zone . We reject null hyothesis
Answer:
33k+32
Step-by-step explanation:
Assign Variables :
Alicia- A
Jamar- J
Tia- T
Write equations :
A = (3k+4)
J= 2(3k+4)
T=4(5+6k)
Simplify equations:
A= 3k+4
J= 6k+8
T= 20+24k
Add:
(3k+4)+(6k+8)+(20+24k)
3k+6k+24k+8+20+4
33k+32
I hope this helps :)
Step-by-step explanation:
3 29/31 + 9 13/14 * 26 6/7 =0
first 26 6/7 = 26 13/14
3 29/31 +( 26 13/14 * 9 13/14)
3 29/31 + 266 32/49
Answer :
270 894/1519 / 270.5585 / 411024/1519
The probability that a randomly chosen person from this group has type B is <u>3/25</u>
The probability that a randomly chosen person from this group has type AB is <u>1/25</u>
The probability that a randomly chosen person from this group has type B or type AB blood is <u>4/25</u>