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vaieri [72.5K]
4 years ago
6

(-12)÷(9.9)= what is the answer to this question

Mathematics
2 answers:
lara [203]4 years ago
7 0
General rule for multiplication or division between 2 numbers:
if you multiply or divide by:
1. same signs, answer is postive
2. different signs, answer is negative

so we have a -12 and a +9.9 so the answer is negative
then you divide 12 by 9.9

so the answer is negatiive, remember that
then divide as if positive
do
12/9.9
multiply by 10/10
120/99
simplify
120/99
factor out the 3/3
40/33
do the division (you can use calculator)
1.212121212121212121212121212
then it is negative so
-1.212121
Lady bird [3.3K]4 years ago
6 0
The answer it <span>-1.212121212121212121212121212</span>
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Step-by-step explanation:

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4 years ago
Claire's music playlist contains songs she bought and songs her mother bought. The ratio of her songs to her mother's songs is 3
Vsevolod [243]

Answer:

B.

Step-by-step explanation:

The ratio of Claire's songs to her mother's songs = 3 : 2

A.

3 : 2 = 3/2

9 : 6 = 9/6 = 3/2

12 : 10 = 12/10 = 6/5

B.

3 : 2 = 3/2

6 : 4 = 6/4 = 3/2

15 : 10 = 15/10 = 3/2

C.

3 : 2 = 3/2

4 : 3 = 4/3

5 : 4 = 5/4

D.

3 : 2 = 3/2

4 : 6 = 4/6 = 2/3

20 : 30 = 20/30 = 2/3

The table which shows the correct ratio and two equivalent ratios is B

7 0
3 years ago
Evaluate the indicated limit algebraically. Change the form of the function where necessary. Please write clearly with descripti
alukav5142 [94]

Answer:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Step-by-step explanation:

We want to evaluate the limit:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}

To do so, we can divide everything by <em>x</em>². So:

=\displaystyle \lim_{x\to \infty}\frac{3+4.5/x^2}{1-1.5/x^2}

Now, we can apply direct substitution:

\Rightarrow \displaystyle \frac{3+4.5/(\infty)^2}{1-1.5/(\infty)^2}

Any constant value over infinity tends towards 0. Therefore:

\displaystyle =\frac{3+0}{1+0}=\frac{3}{1}=3

Hence:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3<em>x</em>²<em>, </em>and in the denominator it is <em>x</em>². So:

\displaystyle \Rightarrow \lim_{x\to\infty}\frac{3x^2}{x^2}

Simplify:

\displaystyle =\lim_{x\to\infty}3=3

The limit of a constant is simply the constant.

We acquire the same answer.

6 0
3 years ago
What is 1/4 (5y-3)+1/16 (12y+17
netineya [11]

What is the question? If you are only trying to expand the expression then the answer would be:

1/4 (5y-3)+ 1/16 (12y+17)

(5y/4) – (3/4) + (12y/16) + (17/16)

1.25y – 0.75 + 0.75y + 1.0625

2y + 0.3125

 

If you are trying to find for y, then you forgot to equate it to 0, that is:

2y + 0.3125 = 0

2y = -0.3125

<span>y = 0.15625</span>

6 0
3 years ago
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