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Nezavi [6.7K]
1 year ago
10

To find the angle of rotation θ between the previous x and y axes and the new x′ and y′ axes, we use the formula: cotangent of 2

theta equals A minus C all over B , where 2θ lies on the interval (0°, 180°).TrueFalse

Mathematics
1 answer:
Tamiku [17]1 year ago
7 0

The equation is the given one:

\cot 2\theta=\frac{A-C}{B}

Which is the same as:

\tan 2\theta=\frac{B}{A-C}

And the interval of the angle θ must be (0°,90°) so, 2θ must be (0°,180°).

So the statement is True.

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(Please help with this, I'm in the middle of a quiz)
astraxan [27]

Answer:

D)16 ft (feet)

Step-by-step explanation:

20x24=256ft

Then you square root that and get 16.

Hope this helps.

6 0
3 years ago
The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)
Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}

Now, we have to find the quotient of the above expression.

So, here we go:

Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)

Now, we will divide the above simplest form with g(x):

\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2

Hence, the quotient is (x-2).


6 0
3 years ago
Read 2 more answers
PLEASSEEEE HELP W THIS QUESTION!!!!
brilliants [131]
X/28 = 5/7
x = 28 * 5 / 7
x = 20

answer
x = 20 ft
3 0
3 years ago
Read 2 more answers
B(n)=1 (-2)^n-1<br> What is the 4th term in the sequence
zzz [600]

Answer:

The fourth term of the sequence B(4) =-8

The sequence is 1,-2,4,-8...

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the sequence

     B(n) = 1(-2)ⁿ⁻¹

Put n=1

    B(1) = 1(-2)¹⁻¹ = 2⁰ =1

Put n=2

   B(2) = 1(-2)²⁻¹ = (-2)¹ =-2

Put n=3

  B(3) =1(-2)³⁻¹ = (-2)² =4

Put n=4

B(4) = 1(-2)⁴⁻¹ =(-2)³ =-8

The sequence

1,-2,4,-8...

5 0
3 years ago
A rain gutter is made from sheets of aluminum that are 16 inches wide by turning up the edges to form right angles. Determine th
blsea [12.9K]

Answer:

Depth of the rain gutter is 8 inches

Step-by-step explanation:

Let’s assume ‘x’ is the depth of the rain gutter

Then the width of the rain gutter can be written as 16 - 2x

Cross sectional area

A = depth x width

Substitute values

A = x*(16 - 2x)

A = 16x – 2x^2

Now according to axis of symmetry for maximum area x = -b/2a

x = -16/2*(-2)

x = 4 inches depth of rain gutter, substitute the value of x to get

Width of rain gutter 16 – 2(4) = 8 inches

Area of the rain gutter for maximum water flow

A = 4 * 8

A = 32 square inch.

8 0
3 years ago
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