How many moles of CsXeF7 can be produced from the reaction of 12.5 LOL of celsium Fluoride with 10.0 mol of xenon hexafloride
1 answer:
You might be interested in
Answer:
The resulting solution contains approximately 666 g of water.
Explanation:
In the initial solution we have:
1g salt : 8g sugar : 200g water
This means that the ratios are:
In the final solution we have:
5g salt: xg sugar: yg water
The new ratios are:
Now we can calculate the amount of sugar in the final solution:
Finally, we calculate the amount of water: