6.75 moles of H₂
Explanation:
We have the following balanced chemical reaction:
Mg + 2 HCl → MgCl₂ + H₂
From the chemical reaction we deduce that if 1 mole of Mg is reating with 2 moles of HCl then 8.30 moles of Mg is reaction with 16.60 moles of HCl, quantity which is over our available 13.5 moles of HCl. The limiting reactant is HCl.
Knowing this we devise the following reasoning:
if 2 moles of HCl produces 1 mole of H₂
then 13.5 moles of HCl produces X moles of H₂
X = (13.5 × 1) / 2 = 6.75 moles of H₂
Learn more about:
balancing chemical equations
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