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Jlenok [28]
3 years ago
10

When do d orbitals start getting filled

Chemistry
2 answers:
Ghella [55]3 years ago
8 0

Answer & Explanation:

D orbitals begin filling with electrons after the orbital found in the 4s sublevel is filled. This occurs because the d sublevel is first found in the.

Marat540 [252]3 years ago
7 0

Answer:

Interesting question.

Explanation:

D orbitals begin filling with electrons after the orbital found in the 4s sublevel is filled.

Have a good day

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How Many Planets Are There In A Galaxy? ​
sergeinik [125]

Answer:

There are infinite planets in a galaxy!

Explanation:

6 0
3 years ago
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The density of an aqueous solution containing 10.0 percent of ethanol (C2H5OH) by mass is 0.984 g/mL. (a) Calculate the molality
Mrrafil [7]

Answer:

a. 2.41 molal

b. 0.21 M

c. 58.5 mL

Explanation:

First of all let's think the data 10 % by mass, which means, that 10 grams from the solute is contained in 100 g of this solution.

So If we know solution density, we can get its volume.

Solution density = Solution mass / Solution volume

0.984 g/ml = 100 g / Solution volume

Solution volume = 100 g/ 0.984g/ml

Volume = 101.6 mL

As we have 10 g of solute, 100 g of solution, we have 90 g of solvent.

Solute mass + Solvent mass = Solution mass

How many moles do we have in 10 g of ethanol?

Molar mass of ethanol: 46.07 g/m

Mass / molar mass = Moles

10 g/ 46.07 g/m = 0.217 mol

This quantity is in 90 g of solvent and 101.6 mL of solution. For molality and molarity, we should use a rule of three to find out the moles in 1 kg of solvent and 1 L of solution.

1 L = 1000 mL

1kg = 1000 g

<u>Molality</u>

90 g _____ 0.217 moles

1000 g _____ (1000 . 0.217)/ 10 = 2.41 molal

Molarity

101.6 mL ___ 0.217 moles

1000 mL ____  (1000 . 0.217) / 101.6 = 0.21 M

What volume of the solution would contain 0.125 mole of ethanol?. Let's think a new rule of three.

0.217 moles of solute ___ are in __ 101.6 mL of solution

0.125 moles of solute___ are in (0.125 . 101.6)/0.217 = 58.5 mL

6 0
3 years ago
Define a balance equations:
Misha Larkins [42]

Doing a Traditional Balance

1

Write down your given equation. For this example, you will use:

C3H8 + O2 --> H2O + CO2

This reaction occurs when propane (C3H8) is burned in the presence of oxygen to produce water and carbon dioxide.

Image titled Balance Chemical Equations Step 2

2

Write down the number of atoms per element. Do this for each side of the equation. Look at the subscripts next to each atom to find the number of atoms in the equation. When writing it out, it's a good idea to connect it back to the original equation, noting how each element appears.

For example, you have 3 oxygen atoms on the right side, but that total results from addition.

Left side: 3 carbon (C3), 8 hydrogen (H8) and 2 oxygen (O2).

Right side: 1 carbon (C), 2 hydrogen (H2) and 3 oxygen (O + O2).

Image titled Balance Chemical Equations Step 3

3

Save hydrogen and oxygen for last, as they are often on both sides. Hydrogen and oxygen are both common in molecules, so it's likely that you'll have them on both sides of your equation. It's best to balance them last.

You'll need to recount your atoms before balancing the hydrogen and oxygen, as you'll likely need to use coefficients to balance the other atoms in the equation.

Image titled Balance Chemical Equations Step 4

4

Start with single elements. If you have more than one element left to balance, select the element that appears in only a single molecule of reactants and in only a single molecule of products. This means that you will need to balance the carbon atoms first.

Image titled Balance Chemical Equations Step 5

5

Use a coefficient to balance the single carbon atom. Add a coefficient to the single carbon atom on the right of the equation to balance it with the 3 carbon atoms on the left of the equation.

C3H8 + O2 --> H2O + 3CO2

The coefficient 3 in front of carbon on the right side indicates 3 carbon atoms just as the subscript 3 on the left side indicates 3 carbon atoms.

In a chemical equation, you can change coefficients, but you must never alter the subscripts.

6

Balance the hydrogen atoms next. Since you have balanced all atoms besides the hydrogen and oxygen, you can address the hydrogen atoms. You have 8 on the left side. So you'll need 8 on the right side. Use a coefficient to achieve this.

C3H8 + O2 --> 4H2O + 3CO2

On the right side, you now added a 4 as the coefficient because the subscript showed that you already had 2 hydrogen atoms.

When you multiply the coefficient 4 times by the subscript 2, you end up with 8.

The other 6 atoms of oxygen come from 3CO2.(3x2=6 atoms of oxygen+ the other 4=10)

7

Balance the oxygen atoms. Remember to account for the coefficients that you've used to balance out the other atoms. Because you've added coefficients to the molecules on the right side of the equation, the number of oxygen atoms has changed. You now have 4 oxygen atoms in the water molecules and 6 oxygen atoms in the carbon dioxide molecules. That makes a total of 10 oxygen atoms.

Add a coefficient of 5 to the oxygen molecule on the left side of the equation. You now have 10 oxygen atoms on each side.

C3H8 + 5O2 --> 4H2O + 3CO2.

The carbon, hydrogen, and oxygen atoms are balanced. Your equation is complete.


Completing an Algebraic Balance

1

Write down the given equation. For this example, we will use:

PCl5 + H2O --> H3PO4 + HCl

2

Assign a letter to each substance.

aPCl5 + bH2O --> cH3PO4 + dHCl

3

Check the number of each element found on both sides, and set those equal to each other.

aPCl5 + bH2O --> cH3PO4 + dHCl

On the left side, there are 2b atoms of hydrogen (2 for every molecule of H2O), while on the right side, there are 3c+d atoms of hydrogen (3 for every molecule of H3PO4 and 1 for every molecule of HCl). Since the number of atoms of hydrogen has to be equal on both sides, 2b must be equal to 3c+d.

Do this for every element.

P: a=c

Cl: 5a=d

H: 2b=3c+d

4

Solve this system of equations to get the numeric value for the coefficients. Since there are more variables than equations, there are multiple solutions. You must find the one where every variable is in its smallest, non-fractional form.

Since P: a = c, we know that c = 1.

Since Cl: 5a = d, we know that d = 5

Since H: 2b = 3c + d, we can calculate b like this:

2b = 3(1) + 5

2b = 3 + 5

2b = 8

b=4

This shows us the values are as follows:

a = 1

b = 4

c = 1

d = 5


Question

How can I balance Na2CO3 + HCl -> NaCl + H2CO3?

Answer

First multiply NaCl by 2, since you have 2 Na on the reactant side. Na2CO3 + HCl -> 2NaCl + H2CO3. Then, since there are now 2 Cl in the product side, multiply HCl by 2. This also has the effect of balancing the hydrogen, and the equation is now balanced as Na2CO3 + 2HCl -> 2NaCl + H2CO3.




5 0
3 years ago
Read 2 more answers
Do solids have spaces between their particles?
telo118 [61]

Answer:

yes

Explanation:

there are still some space in between them

7 0
3 years ago
How many atoms are in one body-centered cubic unit cell of a metal?
Mashcka [7]

Answer:

Option B - 2

Explanation:

In Crystal lattices, there are different types of unit cells namely;

- Hexagonal Closest Packed (HCP)

- Face Centred Cubic (FCC)

- Body Centred Cubic (BCC)

- Simple Centred Cubic (SC)

Now, each of them have a coordination number and also number of atoms per unit cell.

For this question, we are restricted to the body-centered cubic (bcc) unit cell which has a coordination number of 8 and contains 2 atoms per unit cell.

3 0
3 years ago
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