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statuscvo [17]
3 years ago
14

A dry ran the 100-meter dash in 13.4 seconds. Below is a table showing andy's heart rate during the race. What parent function d

oes Andy's data best represent
Mathematics
1 answer:
kodGreya [7K]3 years ago
3 0
We need the data table to answer the question

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On Monday, the ABC Company stock was at $12.80 per share. On Tuesday it gained $3.42, and then lost $9.70 on Wednesday. What is
solong [7]

Answer:

Step-by-step explanation:

12.80+3.42= 16.22

16.22-9.70= 6.52 that's your answer

6 0
3 years ago
Please Help Me : ]
Goryan [66]

Answer:

b

Step-by-step explanation:

the anwser to this question is b i think

5 0
3 years ago
Kim purchased 6 small containers of potato salad and Seth purchased 2 extra
victus00 [196]

Answer:

the difference is that the 2 extra LARGE containers weigh bigger than the

6 small ones

Step-by-step explanation:

6 0
2 years ago
Soulotion to equation if y is =15 when x=2 ,find y when x=8
skelet666 [1.2K]

Answer:

The value of y for x = 8 is 60  .

Step-by-step explanation:

Given expression as :

For x = 2  , y = 15

Let the equation be written with constant k'

So, y = k x

Or, k = \dfrac{y}{x}

∴   k =  \dfrac{15}{2}

<u>Now, again </u>

For x = 8

equation can be written as

   y = k x

Or,  y =  \dfrac{15}{2} × 8

Or,  y = \frac{15\times 8}{2}

∴    y = 15 × 4

I.e  y = 60

Hence The value of y for x = 8 is 60  . Answer

5 0
3 years ago
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
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