4(5x – 6y) + 16x I don’t know how do this problem
1 answer:
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Answer:
Step-by-step explanation:
The given points are
P = (-4,11)
Q = (-5,8)
The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3
The vector QP is
(1,3) or
The magnitude of the vector is
√(1² + 3²) = √(10)
Answer:
The magnitude is √(10).
P = (-4,11)
Q = (-5,8)
The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3
The vector QP is
(1,3) or
The magnitude of the vector is
√(1² + 3²) = √(10)
Answer:
The magnitude is √(10).
Answer:
A. 5.8
Step-by-step explanation:
From the given graph d has two coordinates;
the first coordinates of d = (0, 0)
the second coordinate of d = (-3 , -5), that is x = -3 when traced up and y = -5 when traced horizontal
The distance between the two coordinates = distance of d;
Option A is correct