Ask question

Ask question

All categories

Law Incorporation [45]

3 years ago

12

If $350 is placed in a savings account that earns 3.5% interest applied once a year, and how much would a savings account be wor

th after 10 years?
1) $522.88
2) $426.34
3) $472.50
4) $493.71

1 answer:

melamori03 [73]3 years ago

6 0

Answer:

$493.71

Step-by-step explanation:

350(1 + 0.035/4)^4(10)

You might be interested in

What is the area of the actual square window shown in the scale drawing?

larisa86 [58]

The area of the actual square window = 2.25 m².

<h3>Scale Drawing</h3>

Scale drawing relates the actual length of an object to its length on a paper.

Given a scale of 1 in = 2 m, it means 1 in on paper is about 2 m of the actual length of the object.

Thus:

Length on scale drawing = 0.75 in
Actual length = x

Therefore:

1/2 = 0.75/x

Cross multiply

x = 1.5 m

Area of the actual square window = 1.5² = 2.25 m².

Learn more about scale drawing on:

brainly.com/question/25324744

5 0

2 years ago

Ebony earned scores of 72 70, 81, 99, and 88 on five math tests. Determine her

Minchanka [31]

Let it be x

$\boxed{\sf Average=\dfrac{Sum\:of\:terms}{No\:of\:terms}}$

$\\ \sf\longmapsto \dfrac{72+70+81+99+88+x}{6}=83$

$\\ \sf\longmapsto \dfrac{410+x}{6}=83$

$\\ \sf\longmapsto 410+x=498$

$\\ \sf\longmapsto x=498-410$

$\\ \sf\longmapsto x=88$

6 0

3 years ago

Write the equation of the line parallel to 3x - 4y = 18 that goes through<br> the point (8,-3)

kkurt [141]

Answer:

y=3/4x-9

Step-by-step explanation:

3 0

3 years ago

A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

4 0

3 years ago

Read 2 more answers

33. The perimeter of a room is 22m.lf<br> the length of the room is 6.5m,<br> what is its width?

vredina [299]

The formula for perimeter is 2(Length) + 2(width)

Fill in the known information:

22 = 2(6.5)+ 2(width)

Simplify:

22 = 13 + 2(width)

Subtract 13 from both sides:

9 = 2(width)

Divide both sides by 2:

Width = 4.5m

4 0

3 years ago