Question

A submarine was 200 feet below sea level. It rose to the surface and then dove again to four times its initial depth. The submarine then descended another 300 feet. What was the sub’s final depth? Steps: 1. Write an expression to model the situation. 2. Evaluate the expression. -200 + 200 + 4(–200) + (–300) feet

Answer 1

Answer:

The submarine is 1100 feet below the sea level that is at -1100 feet.

Step-by-step explanation:

We are given the following in the question:

A submarine was 200 feet below sea level.

Since the submarine was below the sea level we can write the position as -200 feet with respect to sea level.

It rose to the surface and then dove again to four times its initial depth.

$-200 + 200 + 4(-200)\text{ feet}$

The submarine then descended another 300 feet.

Total movement in submarine =

$(-200 + 200 + 4(-200) - 300)\text{ feet}$

1. Model for the given situation:

$-200 + 200 + 4(-200)\text{ feet}$

2. Evaluate the expression

$-200 + 200 + 4(-200) + (-300) = -1100\text{ feet}$

Thus, the submarine is 1100 feet below the sea level that is at -1100 feet.

Answer 2

Answer:

-1100

Step-by-step explanation: