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hichkok12 [17]
2 years ago
15

1) Find mZLMN if mZLMT= 23° and mZTMN = 144º.

Mathematics
1 answer:
Nesterboy [21]2 years ago
3 0

Answer:

m<LMN = 167°

Step-by-step explanation:

Given:

m<LMT = 23°

m<TMN = 144°

Required:

m<LMN

SOLUTION:

m<LMN = m<LMT + m<TMN (angle addition postulate)

m<LMN = 23° + 144° (Substitution)

m<LMN = 167°

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eimsori [14]
15 servings because 11.25/0.75=15

3/4=.75
11 1/4=11.25
7 0
3 years ago
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If EM=11, AM=16, and CF=27, what are the lengths of the following sides?
tensa zangetsu [6.8K]

Answer:

18

Step-by-step explanation:

4 0
3 years ago
Write y = x2 + 24x + 144 as a square of binomial.
irina1246 [14]

Answer:

y=(x+12)^2\\

Step-by-step explanation:

To write a quadratic equation into binomial form we can compare the equation into the completing square form of a quadratic equation like this ,

y=a(x-h)^2+k

now since,

y=x^2+24x+144

we can equate both the equations from left hand side to right hand side like this,

x^2+24x+144=a(x-h)^2+k\\

now we solve,

x^2+24x+144=a(x-h)^2+k\\x^2+24x+144=a((x)^2-2(x)(h)+(h)^2)+k\\x^2+24x+144=a(x^2-2hx+h^2)+k\\x^2+24x+144=ax^2-2ahx+ah^2+k\\

now we compare the coefficients of x^2:

1 = a\\

now we compare the coefficients of x :

24=-2ah\\24=-2(1)h\\24=-2h\\\frac{24}{-2}=h\\-12=h\\

now we compare the constants , (constants are the letters which are not associated with any variable in this case the variable is x)

144 = ah^2+k\\144=(1)(-12)^2+k\\144=(1)(144)+k\\144=144+k\\144-144=k\\0=k\\

so now the value we got all the values for the completing square form we plug those in , a = 1 , h = -12 , k = 0 ,

y=a(x-h)^2+k\\y=1(x-(-12))^2+0\\y=(x+12)^2\\

this is the square of a binomial, if you want to verify if we expands this formula by the formula of (a + b)^2 we would get the same result. Thus this is the correct answer.

5 0
3 years ago
A spinner is divided into five colored sections that are not of equal size: red, blue,
pashok25 [27]

Answer:

0.67

Step-by-step explanation:

The total number of spins is

7 + 13 + 20 + 14 + 9 = 63

The numbers of spins that landed on blue, green, and purple are:

13, 20, 9

Total blue, green, purple: 13 + 20 + 9 = 42

Based on the spins that are tabulated, the probability the spinner will land on blue, green, or purple is

42/63 = 2/3 = 0.67

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3 years ago
Need help with this asap
dem82 [27]

Answer:

I cant lie I don't know this answer

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2 years ago
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