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borishaifa [10]
3 years ago
10

How to state the quadrant in which an angle lies in radians?

Mathematics
1 answer:
Gelneren [198K]3 years ago
6 0
Quadrant I is 0 to 90 degrees. In radians, that's 0 to pi/2

Quadrant II is 90 to 180 degrees. In radians, that's pi/2 to pi

Quadrant III is 180 to 270 degrees. In radians, that's pi to 3pi/2

Quadrant IV is 270 to 360 degrees. In radians, that's 3pi/2 to 2pi.

Its best to just memorize this, but if you need it, the conversion from degrees to radians is d*180/pi, where d is the degree of the angle. In the case that you get a negative angle or an angle that is greater than 360 degrees, just add or subtract 360 degrees until you get an angle that is within 0 to 360 degrees.
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Convert the following from decimals to percents
Harlamova29_29 [7]
All you do is multiply the decimal by 100.

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D. 28%
3 0
3 years ago
2x - 3y = 45 and x + y = 10 what is the x - value of the solution of the system
abruzzese [7]

Answer:

x=15

Step-by-step explanation:

This is a simultaneous equation

2x-3y=45 ------------------------------ equation i

x+y=10    -------------------------------equation ii

from equation ii

x+y=10

make x the subject of the matter

we have,

x=10-y

in equation i

substitute x for 10-y

2x-3y=45----------------------i

since x=10-y

we have,

2(10-y) - 3y=45

20-2y=3y=45

collect like terms

-2y-3y=45-20

-5y=25

divide both sides by -5

we have y=-5

substitute y for-5 in equation i

x+y=10

x+-5=10

collect like terms

x=10+5

x=15

therefore

x=15

8 0
3 years ago
Read 2 more answers
What is the surface area of this triangular pyramid?
Simora [160]

Answer: 10 + 10.75 + 10 = 30.75 (but it could also be 31.5)

Step-by-step explanation: ???

5 0
3 years ago
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An arc on a circle measures 295°. The measure of the central angle, in radians, is within which range? 0 to StartFraction pi Ove
ozzi

Answer:

D

Step-by-step explanation:

took the test

8 0
3 years ago
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Find the area of the region under the graph of f on [a, b].<br> f(x) = x2 − 8x + 17; [−1, 2]
Harman [31]

Answer:

The area is 42 area units.

Step-by-step explanation:

The area of a function f(x) on an interval [a,b] is given by:

A = \int\limits^a_b {f(x)} \, dx

Applying to this question:

A = \int\limits^-1_2 {x^2 - 8x + 17} \, dx

Then

F(x) = \frac{x^{3}}{3} - 4x^{2} + 17x

A = F(2) - F(-1)

F(2) = frac{2^{3}}{3} - 4*2^{2} + 17*2 = \frac{8}{3} + 18 = \frac{8 + 3*18}{3} = \frac{62}[3}

F(-1) = frac{(-1)^{3}}{3} - 4*(-1)^{2} + 17*(-1) = -\frac{1}{3} - 21 = \frac{-1 - 21*3}{3} = -\frac{64}[3}

A = F(2) - F(-1) = \frac{62}[3} - (-\frac{64}[3}) = \frac{62+64}{3} = 42

The area is 42 area units.

5 0
3 years ago
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