Answer:
Ihorangi uses 7.65 litres of petrol to and from work
Step-by-step explanation:
If the car Ihorangi drives consumes 7.5 L/100 km
Then for 1 km journey, the car will consume 7.5/100 L
= 0.075 L
If Ihorangi travels 51 km to work and 51 km from work
Therefore Ihorangi travel (51 + 51) km daily to and from work
= 102 km daily
The fuel he consumes daily is 102*0.075 L
= 7.65 L
Answer:(f*g)(x)= 21x^2 -29x -10
Step-by-step explanation:
(3x-5)(7x+2)
21x^2-35x+6x-10
21x^2-29x-10
Answer:
$56
Step-by-step explanation:
100 - (100(0.30)) = 100 - 30 = 70
70 - (70(0.20)) = 70 - 14 = 56
Answer:
4 1/2
Step-by-step explanation:
Apply the fractions formula for division, to
3/4÷1/6
and solve
3/6x4/1
=18/4
Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(18,4) = 2
18/24÷2/2=9/2
Convert to a mixed number using
long division for 9 ÷ 2 = 4R1, so
9/2=4 1/2
Therefore:
3/4÷1/6=4 1/2
4.6/2= 2.3
0.84/2=0.42
0.93/3=0.31
46/2=23
84/2=42
93/3=31
