Marcel and Floyd are playing games at an arcade. Marcel has $8.25 and is only playing $0.25 games. Floyd has $9.75 and is only p
laying $0.75 games. Jorge wants to find the number of games after which Marcel and Floyd will have the same amount of money remaining. Jorge's work is shown below.
1 answer:
Given that,
Marcel has $8.25 and is only playing $0.25 games. Floyd has $9.75 and is only playing $0.75 games.
Jorge wants to find the number of games after which Marcel and Floyd will have the same amount of money remaining.
The attached figure shows the equation that Jorge had :
8.25-0.25x=9.75-0.75x
Subtract 9.75 to both sides
8.25-0.25x-9.75=9.75-0.75x-9.75
-1.5-0.25x=-0.75x
Add 0.25x to the both sides,
-1.5-0.25x+0.25x=-0.75x+0.25x
-1.5=-0.5x
⇒ x = 3
Jorge is incorrect at step 2 where he taken -0.25x to the RHS such that -0.75x+0.25x, he get 0.5x instead of (-0.5x). Hence, From Step 1 to Step 2, Jorge did not add 0.25x correctly to both sides.
You might be interested in
5: THEO = what should happen
EXP = Wha actually happens.
EXP = Wha actually happens.
Answer:
D. $3.79x $15
<em>Brainliest, please!</em>
Step-by-step explanation:
It costs $3.79 per bag of chips, and Mr. Connor can pay NO MORE THAN $15.
Answer:
The required probability is 0.94
Step-by-step explanation:
Consider the provided information.
There are 400 refrigerators, of which 40 have defective compressors.
Therefore N = 400 and X = 40
The probability of defective compressors is:
It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,
That means n=15
Apply the probability density function.
We need to find P(X ≤ 3)
Hence, the required probability is 0.94