1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kumpel [21]
3 years ago
8

Find the interquartile range for the data. {50, 46, 56, 55, 54, 51, 45, 50, 47}

Mathematics
1 answer:
levacccp [35]3 years ago
6 0

Answer:

51

Step-by-step explanation:

I think the answer is 51 because you have to find the number between the first three to the middle

You might be interested in
I NEED HELP!!! PLEASE ANSWER THESE QUESTIONS!
Tanya [424]
Okay just ask and I got you man
8 0
3 years ago
Heyy! i’ll give brainliest please help
ipn [44]

Answer:

Step-by-step explanation:

Always capitalize the names of the seasons

3 0
3 years ago
Read 2 more answers
What is all of the surface area and volume of this Castle? Find the surface area and volume of all the figures below, then out o
motikmotik

Answer:

Step-by-step explanation:

There are a few formulas that are useful for this:

  • lateral area of a pyramid or cone: LA = 1/2·Ph, where P is the perimeter and h is the slant height
  • lateral area of a cylinder: LA = π·dh, where d is the diameter and h is the height
  • area of a rectangle: A = lw, where l is the length and w is the width
  • volume of a cone or pyramid: V = 1/3·Bh, where B is the area of the base and h is the height
  • volume of a cylinder or prism: V = Bh, where B is the area of the base and h is the height

You will notice that for lateral area purposes, a pyramid or cone is equivalent to a prism or cylinder of height equal to half the slant height. And for volume purposes, the volume of a pyramid or cone is equal to the volume of a prism or cylinder with the same base area and 1/3 the height.

Since the measurements are given in cm, we will use cm for linear dimensions, cm^2 for area, and cm^3 for volume.

___

The heights of the cones at the top of the towers can be found from the Pythagorean theorem.

  (slant height)^2 = (height)^2 + (radius)^2

  height = √((slant height)^2 - (radius)^2) = √(10^2 -5^2) = √75 = 5√3

The heights of the pyramids can be found the same way.

  height = √(13^2 -2^2) = √165

___

<u>Area</u>

The total area of the castle will be ...

  total castle area = castle lateral area + castle base area

These pieces of the total area are made up of sums of their own:

  castle lateral area = cone lateral area + pyramid lateral area + cylinder lateral area + cutout prism lateral area

and ...

  castle base area = cylinder base area + cutout prism base area

So, the pieces of area we need to find are ...

  • cone lateral area (2 identical cones)
  • pyramid lateral area (2 identical pyramids)
  • cylinder lateral area (3 cylinders, of which 2 are the same)
  • cutout prism lateral area
  • cylinder base area (3 cylinders of which 2 are the same)
  • cutout prism base area

Here we go ...

Based on the above discussion, we can add 1/2 the slant height of the cone to the height of the cylinder and figure the lateral area of both at once:

  area of one cone and cylinder = π·10·(18 +10/2) = 230π

  area of cylinder with no cone = top area + lateral area = π·1^2 +π·2·16 = 33π

  area of one pyramid = 4·4·(13/2) = 52

The cutout prism outside face area is equivalent to the product of its base perimeter and its height, less the area of the rectangular cutouts at the top of the front and back, plus the area of the inside faces (both vertical and horizontal).

  outside face area = 2((23+4)·11 -3·(23-8)) = 2(297 -45) = 504

  inside face area = (3 +(23-8) +3)·4 = 84

So the lateral area of the castle is ...

  castle lateral area = 2(230π + 52) +33π + 504 + 84 = 493π +692

  ≈ 2240.805 . . . . cm^2

The castle base area is the area of the 23×4 rectangle plus the areas of the three cylinder bases:

  cylinder base area = 2(π·5^2) + π·1^2 = 51π

  prism base area = 23·4 = 92

  castle base area = 51π + 92 ≈ 252.221 . . . . cm^2

Total castle area = (2240.805 +252.221) cm^2 ≈ 2493.0 cm^2

___

<u>Volume</u>

The total castle volume will be ...

  total castle volume = castle cylinder volume + castle cone volume + castle pyramid volume + cutout prism volume

As we discussed above, we can combine the cone and cylinder volumes by using 1/3 the height of the cone.

  volume of one castle cylinder and cone = π(5^2)(18 + (5√3)/3)

  = 450π +125π/√3 ≈ 1640.442 . . . . cm^3

 volume of flat-top cylinder = π·1^2·16 = 16π ≈ 50.265 . . . . cm^3

The volume of one pyramid is ...

  (1/2)4^2·√165 = 8√165 ≈ 102.762 . . . . cm^3

The volume of the entire (non-cut-out) castle prism is the product of its base area and height:

  non-cutout prism volume = (23·4)·11 = 1012 . . . . cm^3

The volume of the cutout is similarly the product of its dimensions:

  cutout volume = (23 -8)·4·3 = 180 . . . . cm^3

so, the volume of the cutout prism is ...

  cutout prism volume = non-cutout prism volume - cutout volume

  = 1012 -180 = 832 . . . .  cm^3

Then the total castle volume is ...

  total castle volume = 2·(volume of one cylinder and cone) + (volume of flat-top cylinder) +2·(volume of one pyramid) +(cutout prism volume)

  = 2(1640.442) + 50.265 +2(102.762) +832 ≈ 4368.7 . . . . cm^3

4 0
3 years ago
a store sells grass seed in small bags and large bags.the small bags have 7 pounds of seed for 27.93 and large bags cost 66.98.w
Nonamiya [84]

Answer

Find out the ratio of price to pound for each bag.

To prove

As given

A store sells grass seed in small bags and large bags.the small bags have 7 pounds of seed for $27.93 .

7 pound = $27.93

Now find out the cost for the 1 pound.

1\ pound\ cost= \frac{27.93}{7}

1 pound cost = $3.99

As given large bags cost $66.98.

Now find out pounds in the large bags.

Let us assume that the number of pounds in the large bags be x.

Than

3.99 × x = 66.98

x = \frac{66.98}{3.99}

x = 16.8 pounds (approx)

Now find out the ratio of  price to pound for each bag.

As small bags weight = 7 pounds

Cost of the small bags = $27.93

\frac{Price\ of\ small\ bag}{Cost\ of\ the\ small\ bags} = \frac{27.93}{7}

As large bags weight = 16.8 pounds

Cost of the large bags = $66.98

\frac{Price\ of\ large\ bag}{Cost\ of\ the\ large\ bags} = \frac{66.98}{16.8}

Hence proved


7 0
3 years ago
Graph the parabola y=-3x^2+24x-42
Usimov [2.4K]
Based on the vertex and table this is the graph.

5 0
3 years ago
Other questions:
  • 10/17 = d/51 solve for D
    7·1 answer
  • What is square root of 126 + square root of 56 in standard form
    9·2 answers
  • Cuales son los divisores comunes de 3,9y12
    10·1 answer
  • SOLVE ASAP PLEASE!! What is the first step in solving the equation 2/3x+1/3x+2=5 ? Subtract 1/3 from each side of the equation.
    5·1 answer
  • What is the gcf of 19 and 22
    10·1 answer
  • Please help meee!!! It's urgent!!!<br><br> What is the equation of the line shown in this graph?
    13·1 answer
  • Draw an angle of 40 degree. copy it's supplementary angle
    8·1 answer
  • The price of a video game at Game Word has increased from $36 to $45 each. What was the percent change?
    8·1 answer
  • What single percentage change is equivalent to a 17% decrease followed by a 12% increase​
    7·1 answer
  • 3 rational number between -3/2 and 0​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!