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kumpel [21]
3 years ago
8

Find the interquartile range for the data. {50, 46, 56, 55, 54, 51, 45, 50, 47}

Mathematics
1 answer:
levacccp [35]3 years ago
6 0

Answer:

51

Step-by-step explanation:

I think the answer is 51 because you have to find the number between the first three to the middle

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Look at the Schoology problem provided below.
lys-0071 [83]

Answer:

k = 4 units

Step-by-step explanation:

Using Pythagoras' identity on the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

k² + 7.5² = 8.5²

k² + 56.25 = 72.25 ( subtract 56.25 from both sides )

k² = 16 ( take the square root of both sides )

k = \sqrt{16} = 4

6 0
3 years ago
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Please help <br> D says (-20,-4)
Aleksandr [31]

Answer:

I think its (1,-1)

tell me if i a correct

6 0
3 years ago
Can someone help me with this question
Alexxx [7]
Vas happening?
You break it down
3 ^5 is 3 x 3 x 3 x 3 x 3 = 729
4 ^ 5 is 4 x 4 x 4 x 4 x 4 = 1024
729 times 1024 = 746,496
12 ^ 10 is 12 x 12 x 12 x 12 x 12 x 12 x 12 x 12 x 12 x 12 = 6.19174e10
So the answer is incorrect
8 0
3 years ago
Read 2 more answers
while shopping for clothes, Tracey spent 38$ less than 3 times what Daniel spent. write and solve an equation to find how much D
alexandr1967 [171]

\bold{\huge{\orange{\underline{Solution}}}}

\bold{\underline{ Given :- }}

  • <u>While </u><u>shopping </u><u>for </u><u>clothes </u><u>Tracey </u><u>spent </u><u>3</u><u>8</u><u>$</u><u> </u><u>less </u><u>than </u><u>3</u><u> </u><u>times </u><u>of </u><u>what </u><u>Daniel </u><u>spent </u>

\bold{\underline{ To\: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>determine </u><u>the </u><u>total </u><u>cost </u><u>spent </u><u>by </u><u>daniel</u>

\bold{\underline{ Let's \: Begin :- }}

Cost spent by Tracey for her clothes = 38$

Let assume the spending by Daniel is x

\bold{\underline{Therefore ,}}

\sf{ x / 3 = 38 }

\sf{ x  = 38 × 3 }

\sf{ x = 114 dollar }

\sf{\red{ Hence,\: Daniel\: spent\: 114 \: dollars\: on \: His\: clothes }}

7 0
3 years ago
A woman has twice as many dimes as quarters in her purse. If the dimes were quarters and the quarters were dimes, she would have
Digiron [165]
If x = # of quarters, then, the # of dimes will be equal to 2x. The total value (z) would be equal to:

z = 0.25x + 0.10(2x)

Then, since you switch the quarters and the dimes, and you have a new total, the resulting equation will be:

1.2 + z  = 0.25(2x) + 0.10(x)

Plug in the values you know:

1.2 + (0.25x + 0.10(2x)) = 0.25(2x) + 0.10(x)

Solve for x:

1.2 + (0.25x + 0.20x) = 0.50x + 0.10x
1.2 + 0.45x = 0.60x
1.2 = 0.15x
x = 1.2/0.15 = 8

This means that there are 8 Quarters in her bag right now. So, the amount of dimes is just 2x which is 16. So your answer will be:

She has 8 Quarters and 16 Dimes in her bag right now. Or, $3.60.

If this doesn't make sense, then tell me. I have some resources where I got the answer from to put it into simplest terms. I have the website if you want.
4 0
3 years ago
Read 2 more answers
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