Answer:
Step-by-step explanation:
Given
Negative integer J
Required
Represent as an inequality of its inverse
The question didn't state if it's additive inverse or multiplicative inverse;
<em>Since the question has to do with negation, I'll assume it's an additive inverse</em>
<em></em>
The inverse of -J is +J
To represent as an inequality (less than or equal), we have:
Solving further, it gives
By using y=mx+b you get y=-3/8x-17/8
Answer:
130*
Step-by-step explanation:
To solve this, you need to isolate/get the variable "u" by itself in the inequality: u = unknown number
2u - 3 < 1 Add 3 on both sides
2u - 3 + 3 < 1 + 3
2u < 4 Divide 2 on both sides to get "u" by itself
u < 2 (u is any number less than 2)
When the inequality sign is >/< (greater than/less than), the dot/endpoint is an open/unfilled circle.
When the inequality sign is ≥/≤ (greater than or equal to/less than or equal to), the dot is a closed/filled circle.
u < 2
Start making a ray by placing an open circle on 2(click on the dot/endpoint to change it to be open if it isn't already), then have the ray point left where the numbers would be decreasing because "u" is any number less than 2. If you can place the end of the ray at the end of the number line.
