Answer:
C
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
6x + 10y = 8 ( subtract 6x from both sides )
10y = - 6x + 8 ( divide each term by 10 )
y = -
x +
= -
x 6 +
← in slope- intercept form
with slope m = -
→ C
In order the numbers are 20, 29, 32, 37, 42.
So that means the median is 32. In order for the median to stay the same one of the three data values must be 32 as well as adding a number to each side of the ends. One 32 or less another 32or more.
The mean right now is: 20+29+32+37+42=160 and there are 5 values.
Mean: 160/5=32
For it to increase by 10 it has to be 42.
extra 3 numbers I used were 31, 32, & 113 (those are your answer)
This simplifies to 29/25
29*4 is equal to 116 and 25 * 4 is equal to 100.
<span>Since 29 is a prime number it can't be simplified anymore</span>
Answer:
The vertex is at (-1,-7).
The answer to 2 is A.
Step-by-step explanation:
<h3>
1st of all, for the vertex:</h3><h3 />
You want to make the absolute value be |0|, and you make that by assuming a x that is the opposite of the number that accompanies it.
In this case:

Because:

Then:

And, by making the absolute value equal 0 when finding x, you're left with:

<h3>
Secondly, for the domain and range question:</h3>
The easiest way is to graph, or make a table of values and see where the graph points.
I graphed it for you.
You can clearly see how the vertex, at (-1,-7) is the lowest point, telling you that the range is from that point upwards, or

Then, because you're dealing with absolute values, which never bend and make perfect 90° angles at their vertex, it is safe to assume both lines never touch and continue to opposites ends of the x-axis, or (-infinity, infinity) which is your domain.
<h2><em>Feel</em><em> </em><em>free</em><em> </em><em>to</em><em> </em><em>ask</em><em> </em><em>if</em><em> </em><em>you</em><em> </em><em>need</em><em> </em><em>any</em><em> </em><em>extra</em><em> </em><em>help</em><em>.</em><em> </em><em>:</em><em>)</em></h2>