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True [87]
3 years ago
10

What do I do in an algebraic equation when x and y are connected (xy)?

Mathematics
2 answers:
tia_tia [17]3 years ago
7 0

Answer: Distributive property

Step-by-step explanation: I do believe in questions like this you would distribute from the perenthisis (right?)

olga_2 [115]3 years ago
7 0

Answer:

you would have to distribute it

Step-by-step explanation:

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A local fast-food restaurant can serve
Marizza181 [45]

Answer:

4 hours, 150 x 4 = 600 pls give brainliest

5 0
3 years ago
What is the solution to the equation -√(15+x)=-3?
marin [14]
So, the negative would be divided out to make it 3, then square both sides to get rid of the square root and get 9, then subtract 15 and you get -6.  <span />
7 0
3 years ago
Read 2 more answers
Part A: Solve -np 70 &lt; 40 for n. Show your work. (4 points)
ololo11 [35]
Part A:

 -np - 70 < 40
                          +70
                   -np < 110
                      -n < 110/p

Part B

      4w-7k=28
-7k=28-4w
7k=4w-28
k=4/7w-4
6 0
3 years ago
The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml
irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.63}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.63}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

8 0
3 years ago
Solve 4(2a-1) = -10(a-5)
densk [106]
Firstly, you've got to expand the brackets, this becomes;
8a-4= -10a+ 50
You've then got to eliminate the -10a and you do this by adding 10a to both sides,
This then becomes 18a-4=50
You've then got to add 4, to eliminate this, which then becomes 18a=54
You've then got to divide both sides by 18, and this becomes 3.
Therefor, a=3
Hope this helps :)
4 0
3 years ago
Read 2 more answers
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