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3 years ago

What do I do in an algebraic equation when x and y are connected (xy)?

Mathematics

2 answers:

tia_tia [17]3 years ago

7 0

Answer: Distributive property

Step-by-step explanation: I do believe in questions like this you would distribute from the perenthisis (right?)

olga_2 [115]3 years ago

7 0

Answer:

you would have to distribute it

Step-by-step explanation:

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Evaluate the summation of negative 5 n minus 1, from n equals 3 to 12..

NARA [144]

The summation of negative 5 n minus 1, from n equals 3 to 12 can be expressed as

n = 3/12

substitute the value of n to the equatio

-5n – 1

-5( 3/12 ) -1

-9/4

5 0

3 years ago

INTERPRETING EXPRESSIONS: <br> ln the expression 9x - 9, the variable is ___

podryga [215]

The variable is X .........

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3 years ago

Fine the surface of one yard.<br><br>please help .-.

ale4655 [162]

Answer:

1) 34 square meters

2) 21 square yards

Step-by-step explanation:

1) 7x4=28

1/2x3x2x2=6

28+6= 34 square meters

2)3x3=9

1/2x3x2x4=12

9+12= 21 square yards

6 0

2 years ago

Please see the image and help with this homework problem. thank you!

dimulka [17.4K]

we have the function

$E=\sin \frac{\pi}{14}t$

Part a

For t=7

substitute in the given function

$\begin{gathered} E=\sin \frac{\pi}{14}7 \\ E=1 \end{gathered}$

For t=14

$\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}$

For t=21

$\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}$

For t=28

$\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}$

For t=35

$\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}$

Observation: The values of E varies from -1 to 1, including the zero

Part B

Remember that

The Period goes from one peak to the next

Period=2pi/B

B=pi/14

Period=(2pi)/(pi/14)=2pi*14/pi=28

<h2>the period is 28 days</h2>

6 0

1 year ago

Pizzeria Napoli sells a round pizza with diameter 16 inches and a square pizza with side length 15 inches. Which of the two shap

zavuch27 [327]

Answer: Square, 24 square inches

Step-by-step explanation:

Given

Diameter of round pizza $d=16\ in.$

Side of square pizza $a=15\ in.$

Area of circle $\pi r^2$

The area of a square is $a^2$

$\therefore \text{Area of round Pizza}=\pi \times (\frac{16}{2})^2\\\Rightarrow A_1=\pi \times 8^2=201.088\ in.^2$

The area of square pizza is

$A_2=15^2=225\ in.^2$

Clearly, the area of square pizza is more and the difference in their area is

$\Rightarrow A_2-A_1=225-201.088=23.91\approx\ 24\ in.^2$

6 0

2 years ago