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Mkey [24]
2 years ago
8

If possible, how can I write y=2x -1 in the mx+b=y form?

Mathematics
2 answers:
mario62 [17]2 years ago
8 0

Answer:

2x-1=y

Step-by-step explanation:

You currently have y=2x-1 in y=mx+b form.

All we have to do is reorganize the terms into: mx+b=y

PIT_PIT [208]2 years ago
6 0

Answer:

The answer is 2x-1=y

Hope this helped!

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shepuryov [24]

Answer:

The two odd numbers are 15 and 17

Step-by-step explanation:

Given

<em>Let the odd numbers be represented with x and y</em>

<em>Let x be the greater number</em>

<em></em>x + 5y = 92<em></em>

<em></em>

<em>Required</em>

Find x and y

Since x and y are consecutive odd numbers and x is greater, then

x = y + 2

Substitute y + 2 for x in x + 5y = 92<em></em>

<em></em>y + 2 + 5y = 92<em></em>

<em></em>

Collect Like Terms

<em></em>y + 5y = 92 - 2<em></em>

<em></em>6y = 90<em></em>

Divide both sides by 6

\frac{6y}{6} = \frac{90}{6}

y = \frac{90}{6}

y = 15

Substitute 15 for y in x = y + 2

x = 15 + 2

x = 17

<em>Hence; the two odd numbers are 15 and 17</em>

4 0
2 years ago
Find the inverse <br> f(x)=(2x-3)^2 -1
boyakko [2]
2 is the answer ok great
8 0
2 years ago
The product of the roots of 5 - 2m - 3m^2 = 0 is:<br> A. -5/3<br> B. -3/5<br> C. 5/3
dimaraw [331]
<span>m= <span><span><span><span>−5/</span>3 </span></span></span></span><span>   ,swnkadkjkkjmd,m,mdas</span>
7 0
3 years ago
Read 2 more answers
10 pts!!
Leni [432]

Answer:

its going by threes

Step-by-step explanation:

from ( 4,3 ) ( 2,6 )

5 0
2 years ago
Solve the equation x+3/x-4 = x-5/x+4
Serga [27]

Answer:

\large\boxed{x=\dfrac{1}{2}}

Step-by-step explanation:

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\\\\\text{Domain:}\ x-4\neq0\ \wedge\ x+4\neq0\\\\x\neq4\ \wedge\ x\neq-4\\\\D:x\in\mathbb{R}-\{-4,\ 4\}

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\qquad\text{cross multiply}\\\\(x+3)(x+4)=(x-4)(x-5)\qquad\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x)(x)+(x)(4)+(3)(x)+(3)(4)=(x)(x)+(x)(-5)+(-4)(x)+(-4)(-5)\\\\x^2+4x+3x+12=x^2-5x-4x+20\qquad\text{combine like terms}\\\\x^2+(4x+3x)+12=x^2+(-5x-4x)+20\\\\x^2+7x+12=x^2-9x+20\qquad\text{subtract}\ x^2\ \text{from both sides}\\\\7x+12=-9x+20\qquad\text{subtract 12 from both sides}\\\\7x=-9x+8\qquad\text{add}\ 9x\ \text{to both sides}\\\\16x=8\qquad\text{divide both sides by 16}\\\\x=\dfrac{8}{16}\\\\x=\dfrac{8:8}{16:8}\\\\x=\dfrac{1}{2}\in D

7 0
2 years ago
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