Which equation correctly applies the law of cosines to solve for an unknown angle measure?
2 answers:
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Answer:
Verified
Area = 13.12 square units.
Step-by-step explanation:
Let the given points / vertices of the parallelogram be represented as follows:
A(2,-1,1),
B(5, 1,4),
C(0,1,1),
D(3,3,4)
In vector notation, we can have;
A = 2i - j + k
B = 5i + j + 4k
C = 0i + j + k
D = 3i + 3j +4k
One of the ways to prove that a quadrilateral is a parallelogram is to show that both pairs of opposite sides are parallel.
(i) Now, let's find the various sides of the assumed parallelogram. These sides are:
AB = B - A = [5i + j + 4k] - [2i - j + k] <em>open the brackets</em>
AB = 5i + j + 4k - 2i + j - k <em>collect like terms and solve</em>
AB = 5i - 2i + j + j - k + 4k
AB = 3i + 2j+ 3k
BC = C - B = [0i + j + k] - [5i + j + 4k] <em>open the brackets</em>
BC = 0i + j + k - 5i - j - 4k <em>collect like terms and solve</em>
BC = 0i - 5i + j - j + k - 4k
BC = -5i + 0j - 3k
CD = D - C = [3i + 3j +4k] - [0i + j + k] <em>open the brackets</em>
CD = 3i + 3j + 4k - 0i - j - k <em>collect like terms and solve</em>
CD = 3i - 0i + 3j - j + 4k - k
CD = 3i + 2j + 3k
DA = A - D = [2i - j + k] - [3i + 3j +4k] <em>open the brackets</em>
DA = 2i - j + k - 3i - 3j - 4k <em>collect like terms and solve</em>
DA = 2i - 3i - j - 3j + k - 4k
DA = - i - 4j - 3k
AC = C - A = [0i + j + k] - [2i - j + k] <em>open the brackets</em>
AC = 0i + j + k - 2i + j - k <em>collect like terms and solve</em>
AC = 0i - 2i + j + j + k - k
AC = - 2i + 2j +0k
BD = D - B = [3i + 3j + 4k] - [5i + j + 4k] <em>open the brackets</em>
BD = 3i + 3j + 4k - 5i - j - 4k <em>collect like terms and solve</em>
BD = 3i - 5i + 3j - j + 4k - 4k
BD = - 2i + 2j + 0k
(ii) From the results in (i) above, it has been shown that;
AB is equal to CD, and that implies that AB is parallel to CD. i.e
AB = CD => AB || CD
<em>Also,</em>
AC is equal to BD, and that implies that AC is parallel to BD. i.e
AC = BD => AC || BD
(iii) Therefore, ABDC is a parallelogram since its opposite sides are equal and parallel.
(B) Now let's calculate the area of the parallelogram.
To calculate the area, we find the magnitude of the cross product between any two adjacent sides.
In this case, we choose sides AC and AB.
Area = | AC x AB |
Where;
AC X AB = i(6 - 0) - j(-6 - 0) + k(-4 -6)
AC X AB = 6i + 6j - 10k
|AC X AB| =
|AC X AB| =
|AC X AB| =
|AC X AB| = 13.12
Therefore the area is 13.12 square units.
PS: The diagram showing this parallelogram has been attached to this response.
Find the intersection point between the 2 restraint equations:
Substitute back in to find y-value:
P is maximized at point (12,6)
Substitute back in to find y-value:
P is maximized at point (12,6)