Answer:
I got x = 1
Step-by-step explanation:
First to isolate the variable you add 3 to both sides which will give you 1/2x is less than or equal to 2. Then divide both sides by 1/2 and you will get x = 1. To check the answer I just did:
![1/2(1) -3 \leq -1\\1/2 -3\leq -1\\-2.5\leq -1](https://tex.z-dn.net/?f=1%2F2%281%29%20-3%20%5Cleq%20-1%5C%5C1%2F2%20-3%5Cleq%20-1%5C%5C-2.5%5Cleq%20-1)
And since -2.5 is less than -1 this statement is true. x does in fact equal 1
B should be the only correct answer.
Answer:
Step-by-step explanation:
If x - 1 is a factor of the cubic, then 1 should result in 0 when you put it in the cubic for x. Does it?
f(1) = 2(1)^3 - 15(1)^2 + 22(1) + 15
f(1) = 2 - 15 + 22 + 15
f(1)= 24.
No the result is not zero. So x - 1 is not a factor.
However there must be something that makes this cubic go to zero. The easiest way to find it is to graph it.
The numbers that do make this zero are -0.5, 3, 5
Which mean that the factors are (2x+1)(x-3)(x - 5)
C^2-64 is a square roots factoring one. you take the square root of c^2 which is c and then the square root of 64 which is 8 or -8 so the answer is (c-8)(c+8). and it is a special product