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Brilliant_brown [7]
3 years ago
12

Joelle has $15.75. She spent $6.38 at the store.

Mathematics
2 answers:
AVprozaik [17]3 years ago
8 0

Answer:

B.   x + 6.38 = 15.75

Step-by-step explanation:

Download docx
Alborosie3 years ago
4 0
X + 6.38 = 15.75<span> would be the answer 
      x=9.37
for the first option, you are not adding 15.75 and x together. 
for the second option, it is correct, because in the problem, it is giving the operation, 15.75-6.38=x. when you turn it do inverse operation, you get </span><span>x + 6.38 = 15.75. 
for the third option, it doesn't make sense and it's not doing what the problem is asking for.
for the fourth option, you are not multiplying. you are subtracting </span>15.75 by<span> 6.38 to get x.</span>
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If 3* = 1 What will be the value of x?​
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Answer:

X=0

Step-by-step explanation:

It is a law that

{a}^{0}  = 1 \:  \:  \:  \:

Number( a) shouldn't be zero.

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3 years ago
You and three friends are going to the fair. The cost for
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Answer:

$17 on food per person

Step-by-step explanation:

The cost of parking a car is $5

Assuming that the friends used one car, then the parking cost=$5

Admission cost is 19

For three people, Admission cost =19*3=57

TOTAl COSTS=Parking cost+Admission cost

TOTAl COSTS=57+5=62

Remaining amount can be used for food

FOOD= 113-62=51

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I hope this was helpful and clear to follow

3 0
3 years ago
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Which values of m and b will create a system of equations with no solution? Select two options. y = mx + b y = –2x + A system of
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Answer:

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Step-by-step explanation:

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How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antif
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440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze

<em><u>Solution:</u></em>

Let "x" be the gallons of 80 % antifreeze added

Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze

Final mixture is x + 80

Therefore, we can frame a equation as:

"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze

Thus, we get,

x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

x \times \frac{80}{100} + 80 \times \frac{15}{100} = (x+80) \times \frac{70}{100}\\\\0.8x + 80 \times 0.15 = (x+80) \times 0.7\\\\0.8x+12 = 0.7x+56\\\\0.8x-0.7x=56-12\\\\0.1x = 44\\\\x = \frac{44}{0.1}\\\\x = 440

Thus 440 gallons of 80 % antifreeze solution must be mixed

4 0
3 years ago
What is the GCF of 8x^3y^2+20x^2y^4?
DochEvi [55]

Answer:

B) 4x^2y^2

Step-by-step explanation:

8x^3y^2+20x^2y^4

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So the answer is B

5 0
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