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dem82 [27]
3 years ago
6

I need so much help please

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
6 0

Answer:

the Answer will be letter B

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What is the solution to this equation?<br> x-8=15<br><br> A)x=13<br> B)x=17<br> C)x=7<br> D) x=23
Blababa [14]

Hi there! :)

<u><em>Answer:</em></u>

<u><em>x=23</em></u>

<u><em>*The answer must have a positive sign.*</em></u>

Step-by-step explanation:

This lesson it's about addition property of equality.

First, you add by 8 from both sides of an equation.

x-8+8=15+8

And then, you add by the numbers. Simplify and solve.

15+8=23

Final answer: → x=23

Hope this helps!

Thanks!

-Charlie

Have a great day!

:)

:D

3 0
3 years ago
Helpppppp hurry and no links
Alexeev081 [22]

Step-by-step explanation:

6.3%

that is the correct answer

4 0
2 years ago
Read 2 more answers
8+8- 19=??<br> pls help and thank u
kumpel [21]
-3 the answer is -3 ight
4 0
3 years ago
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The area is approximately __ square units,.<br><br> use 3.14 for pi
fenix001 [56]
757 units squared. Here is work:

7 0
3 years ago
A new screening test for Lyme disease is developed for use in the general population. The sensitivity and specificity of the new
Anit [1.1K]

Answer:

predictive value of a positive test = 18.18%

predictive value of a negative test = 94.03%

Step-by-step explanation:

Sensitivity = 60% = 0.6

Specificity = 70% = 0.7

Let True Positive = TP

True Negative = TN

False Negative = FN

Sensitivity = \frac{TP}{TP + FN} \\0.6 = \frac{TP}{TP + FN} \\0.6TP + 0.6FN = TP\\0.4TP = 0.6FN\\TP = 1.5 FN

Specificity = \frac{TN}{TN + FP} \\0.7 = \frac{TN}{TN + FP} \\0.7TN + 0.7FP = TN\\0.7FP = 0.3 TN\\TN  = 7/3 FP

Prevalence = 10% = 0.1

Three hundred people are screened, T_{total} = 300

Total number of people having the disease, T_{disease} = ?

Prevalence = \frac{T_{disease} }{T_{total} } \\0.1 =  \frac{T_{disease} }{300 }\\T_{disease} = 30

T_{disease} = TP + FN\\30 = TP + FN

But TP = 1.5 FN

30 = 1.5 FN + FN

30 = 2.5 FN

FN = 30/2.5

FN = 12

TP = 1.5 FN = 1.5 * 12

TP = 18

FP + TN = T_{total} - T_{disease} \\FP + TN = 300 - 30\\FP + TN = 270\\FP + \frac{7}{3} FP = 270\\\frac{10}{3} FP = 270\\FP = 27 * 3\\FP = 81

81 + TN = 270

TN = 189

To calculate the Predictive value of positive test (PPT)

PPT = \frac{TP}{TP + FP} * 100\\PPT = \frac{18}{18+81} * 100\\PPT = \frac{18}{99} * 100\\PPT = 18.18 \%

To calculate the Predictive value of negative test (PNT)

PPT = \frac{TN}{FN + TN} * 100\\PPT = \frac{189}{189+12} * 100\\PPT = \frac{189}{201} * 100\\PPT = 94.03 \%

7 0
3 years ago
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