Question

Solve the following quadratic formula and enter the solutions below from smallest to largest. Round to the nearest tenth if necessary.
Equation: 4x2+8x+7=4

Solution: Answer
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Answer 1

Answer:

$\:x=-\frac{3}{2},x=-\frac{1}{2}$

Step-by-step explanation:

Subtract 4 from both sides:

$4x^2+8x+7-4=4-4$

Simplify:

$4x^2+8x+3=0$

Solve with the quadratic formula:

$x_{1,\:2}=\frac{-8\pm \sqrt{8^2-4\cdot \:4\cdot \:3}}{2\cdot \:4}$

$x_{1,\:2}=\frac{-8\pm \:4}{2\cdot \:4}$

Separate the solutions:

$x_1=\frac{-8+4}{2\cdot \:4},\:x_2=\frac{-8-4}{2\cdot \:4}$

The solutions to the quadratic equation are:

$\:x=-\frac{3}{2},x=-\frac{1}{2}$

Answer 2

GIVEN:

• Equation:— 4x² + 8x + 7 = 4

ANSWER:

On simplifying equation, we get

• 4x² + 8x + 7 = 4
• 4x² + 8x + 7 – 4 = 0
• 4x² + 8x + 3 = 0

Now, We'll split the middle term to get the solution.

So, 4x² + 6x + 2x + 3 = 0

• 2x(2x + 3) + 1(2x + 3) = 0
• (2x + 1)(2x + 3) = 0
• x = – 1/2 ; – 3/2