50 pts , i need the correct answer, my patient is gone because so many ppl put fake answers, just give the right answer i dont h
ave the energy to even say pls anymore.
1 answer:
Answer:
Hello! Sorry about your luck before although im 99% sure my answer is correct.
Answer: area is 180
Step-by-step explanation:
Ok so first starting off im going to calculate the area for each shape serperately and add them up since thats easier so as demonstrated in the picture the rectangle is 25 because i multiply by base × height and the base and height is 5 and 5 pointed in the picture so thats 25 although i didnt calculate the rest because the base and height is the same for each so we can just do 25 × 6 to get all the rectangles so 25 × 6 = 150 now we got the easy part out of the way now we should do the triangles I pointed to the base and height for that on the left the base being 5 and the height being 3 5 × 3 = 15 BUT WAIT this isn't are area for the triangles because when finding area for triangles we have to divide by 2 so... 15 ÷ 2 = 7.5 since there are 4 of those triangles I dont have to solve for the rest because i can just do 7.5 × 4 so...
7.5 × 4 = 30 now we just combine those areas together! so... 150 + 30 = 180 so 180 is our area HOPE THAT HELPS!
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one way would be to factor
I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have
it goes like this:
for a polynomial with real coefients, consider .
after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have
We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root
to get the negative roots, we evaluate f(-x) and see how many times the root changes
signs are (-, -, -, +). there was 1 change in sign
so the function has 1 real negative root
a total of 2 real roots
a function of degree can have at most,
roots
our function is degree 6 so it has 6 roots
if 2 are real, then the others must be complex
6-2=4 so there are 4 complex roots
you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots