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3 years ago

∆ABC is dilated using a scale factor of 12 to produce ∆A'B'C'.

Mathematics

1 answer:

Contact [7]3 years ago

7 0

Answer:

C, F.

Step-by-step explanation:

All angle measures are preserved in a dilation. And if all angle measures are preserved, it makes the triangles similar by the AA similarity theorem.

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The diagram below shows a triangle with base (x+5) and height 2x inside a shaded rectangle with length (3x+1) and width (3x-5).

Ilya [14]

Answer:

3 for the first one 2ed one is 5

Step-by-step explanation:

6 0

3 years ago

Find the fifth term in the sequence that is defined as follows an=n2+2

Angelina_Jolie [31]

A(5) = 2 + 5^2 = 2 + 25 = 27
Step-by-step explanation:
This sequence is defined as a(n) = 2 + n^2.
Thus, a(1) = 2 + 1^2 = 2 + 1 = 3
Then a(5) = 2 + 5^2 = 2 + 25 = 27

8 0

3 years ago

HELP ASAP!! I don't understand this question!

Veseljchak [2.6K]

Answer:

I think that you have to multiply the angles with each other and thats how you get your answer. Can I get Branliest?

Step-by-step explanation:

7 0

3 years ago

Which function has an average rate of change of -4 over the interval [-2,2]?

kolbaska11 [484]

Only p(x) has an average rate of change of -4 over [-2, 2].

Find the average rate of change of each given function over the interval [-2, 2]]:

The average rate of change of m(x) over [-2, 2]:

<h3>What is the average rate?</h3>

The average rate of change = $\frac{m(b)-m(a)}{b-a}$

Where, a = -2, m(a) = -12

b = 2, m(b) = 4

Plug the values into the equation

The average rate of change

$=\frac{4-(-12)}{2-(-2)} =\frac{16}{4}$

The average rate of change = 4

The average rate of change of n(x) over [-2, 2]:

The average rate of change = $\frac{n(b)-n(a)}{b-a}$

Where, a = -2, n(a) = -6

b = 2, n(b) = 6

Plug the values into the equation

The average rate of change

$=\frac{6-(-6)}{2-(-2)} \\=\frac{12}{4}$

The average rate of change = 3

The average rate of change of q(x) over [-2, 2]:

The average rate of change = $\frac{q(b)-q(a)}{b-a}$

Where, a = -2, q(a) = -4

b = 2, q(b) = -12

Plug the values into the

The average rate of change = $\frac{-4-12}{2-(-2)}$

= $\frac{-16}{4}$

The average rate of change = -2

The average rate of change of p(x) over [-2, 2]:

The average rate of change = $\frac{p(b)-p(a)}{b-a}$

Where, a = -2, p(a) = 12

b = 2, p(b) = -4

Plug the values into the equation

The average rate of change = $\frac{-4-12}{2-(-2)}$

$=\frac{-16}{4}$

The average rate of change = -4

The answer is D.

Only p(x) has an average rate of change of -4 over [-2, 2].

To learn more about the average rate of visit:

brainly.com/question/8728504

#SPJ1

8 0

2 years ago

What is the degree of differential equation? ?

Delicious77 [7]

Answer:

Degree = 1

Step-by-step explanation:

Given:

The differential equation is given as:

$\frac{d^2y}{dx^2}+(\frac{dy}{dx})^2+6y=0$

The given differential equation is of the order 2 as the derivative is done 2 times as evident from the first term of the differential equation.

The degree of a differential equation is the exponent of the term which is the order of the differential equation. The terms which represents the differential equation must satisfy the following points:

They must be free from fractional terms.

Shouldn't have derivatives in any fraction.

The highest order term shouldn't be exponential, logarithmic or trigonometric function.

The above differential equation doesn't involve any of the above conditions. The exponent to which the first term is raised is 1.

Therefore, the degree of the given differential equation is 1.

6 0

3 years ago