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Nina [5.8K]
3 years ago
5

Which of the following problem types CANNOT be solved using the law of sines?

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
4 0
Law of sines in a triangle with angles A, B, C and sides a,b,c states that 
 (sin A)/a =(sinB)/b = (sinC)/c  
 To use the above ratios, you need at least one angle and one side and one of either an angle or a side. So SSS and AAA don't work
notsponge [240]3 years ago
4 0

Answer:

B) SSS C AAA D) SAS

Step-by-step explanation:

The sine rule is used when we are given

a) Two angles and one side (SAA)

b) Two angles and included side (ASA)

Sine rule can not be used in SSS,AAA or SAS.

Among the given options sine rule can not be used in cases B) SSS C AAA D) SAS

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Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De
Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is,\lambda=\frac{1}{\mu}=\frac{1}{7}.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx

                      =\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

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3 years ago
This box can be packed with 48 unit cubes. The edge length of each unit cube is 1 meter. What is the volume of the box?
olga nikolaevna [1]
A cube has six faces so 48/6 is the length of one edge.
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so 48/6= 8
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