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3 years ago

Is it possible for the perimeter of a figure to change after its reflected?

Mathematics

2 answers:

Lunna [17]3 years ago

7 0

Alright, lets get started.

Please refer the diagram I have attached.

There is a triangle ABC having co-ordinates (1,3), (5,2) and (4,-1)

When we make a reflection of this triangle names A'B'C', the co-ordinates are changed (-1,3), (-5,2) and (-4,-1)

But the length of each side remains same.

So, if the length of each side will remain same after its reflected, so perimeter will also be same.

So,after reflection, the perimeter of a figure is not changed. : Answer

Hope it will help :)

ch4aika [34]3 years ago

3 0

No, reflections do not chage shape, size or area. The only transformation that does that is dilation.

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For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r < d. n = −67, d = 8

Firlakuza [10]

Answer:

$q = 8$

$r = 3$

Step-by-step explanation:

Given

$n = dq + r$

$0 \le r < d$

$n = 67$ --- not -67

$d = 8$

Required

Find q and r

Substitute values for d and b

$n = dq + r$

$67 = 8 * q + r$

$67 = 8q + r$

Make q the subject

$q = \frac{67 - r}{8}$

$0 \le r < d$ means that r is less than 8 but greater than or equal to 0

And r and q are integers.

Let $r = 3$

$q = \frac{67 - 3}{8}$

$q = \frac{64}{8}$

$q = 8$

No other true values of r and q can be gotten.

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Vaselesa [24]

Answer: 582.7526

Step-by-step explanation:

p =3,14

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r^2=44.89

SA= 3,14*44.89+3,14*6,7*21= 582,7526

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Let v be the volume of a sphere, s be the surface area of the sphere, and r be the radius of the sphere. which equation represen

MakcuM [25]

Let
v-------> the volume of a sphere
s-------> the surface area of the sphere
r------> the radius of the sphere

we know that
v=(4/3)*pi*r³-----> v=(r/3)*4*pi*r²------> equation 1
and
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substitute equation 2 in equation 1
so
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the answer is
the equation that represents the relationship between these three measures
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