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3 years ago

The Kings Dominion Gold Pass costs $89. If you buy it the first week of

Mathematics

1 answer:

Eddi Din [679]3 years ago

7 0

Answer:

$75.65

Step-by-step explanation:

1 - .15 = .85 = 85% of the price is what you pay

89 • .85 = $75.65

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PLEASE HELP!! What is the value for y? Enter your answer in the box. y =

Mamont248 [21]

Answer:

y=28

Step-by-step explanation:

1. As ABC is an isosceles triangle, that means that angle A is congruent to angle B, which means angle B measures 34˚.

2. The sum of the angles of a triangle add up to 180˚. So, make an equation:

A+B+C=180

As we already know A and B, plug them in:

34+34+C=180

Then solve:

C=112˚

3. As we know that C=4y, we can solve for y: 112/4=28

6 0

4 years ago

Read 2 more answers

A screening of 1,250 teenage boys shows 15 have high blood pressure. What is the probability a teenage boy will have high blood

Lyrx [107]

To find this just divide 15 by 1250 and get 0.012
to find the percent just multiply 0.012 by 100 : 1.2%
the answer is 1.2%

4 0

3 years ago

Cassie needs at least $140 to buy a graphing calculator for math class. Currently she has $30 saved and her neighbor tells her s

UkoKoshka [18]

Answer:

Step-by-step explanation:

140 - 30 =110

110 ÷ 10 = 11

answer is 11 hours

8 0

3 years ago

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What is the equation of this line in slope-intercept form

Ugo [173]

Answer:

y=3/5x+3 i think

Step-by-step explanation:

3 is the y intercept, and to find the slope its rise over run so 3 up and 5 to the side, i hope this helps!!

5 0

3 years ago

Find dy/dx and d2y/dx2. x = cos(2t), y = cos(t), 0 < t < π

pogonyaev

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$

$y=\cos t\implies\dfrac{\mathrm dy}{\mathrm dt}=-\sin t$
$x=\cos2t\implies\dfrac{\mathrm dx}{\mathrm dt}=-2\sin2t=-4\sin t\cos t$
$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{-\sin t}{-4\sin t\cos t}=\dfrac14\sec t$

Let $z=\dfrac{\mathrm dy}{\mathrm dx}$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}=\dfrac{\frac{\mathrm dz}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$
$\implies\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac{\mathrm d}{\mathrm dt}\left[\frac14\sec t\right]}{-4\sin t\cos t}=\dfrac{\frac14\sec t\tan t}{-4\sin t\cos t}=-\dfrac1{16}\sec^3t$

4 0

4 years ago