In the first 100 pages there are 10 pages with numbers 40-49 ( that is total of 11 4's) and another 4 in the units, 10's , 20's, .... 90's ( not including 40's) That is total of 9 4's.
So in first 100 pages there are 20 4's.
therefore there are 20 4's on pages 101-200 and another 20 4's on pages 201-300.
On pages 301 to 352 there are 15 4's.
answer is 3*20 + 15 = 75.
This is useful so that you can come up with a quick answer rather then sit down with paper to solve the whole problem.
It could be the x-axis or the y-axis (not enough information)
Answer:
5.36
Step-by-step explanation:
Given that:
<BAD = <CAE, therefore, BD = EC
Let's take x to be the length of BD = EC
BD + DE + EC = BC
BC = 20,
BD = EC = x
DE ≈ 9.28
Thus,
x + 9.28 + x = 20
x + x + 9.28 = 20
2x + 9.28 = 20
Subtract 9.28 from both sides
2x + 9.28 - 9.28 = 20 - 9.28
2x = 10.72
Divided both sides by 2 to solve for x
BD ≈ 5.36
Answer:
111
Step-by-step explanation:
360 - 65 - 106 - 78 = 111
