Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
Note: <em>The missing graph is attached below. </em>
Answer:
'linear decreasing' best describes interval C on the graph shown.
Step-by-step explanation:
Note: <em>The missing graph is attached below. </em>
From the attached graph, it is easy to figure out that the interval C on the graph shown is showing a straight line. So the graph of the function would be linear.
Also on the interval C, the value of y is decreasing as the value of x increase. So, the slope of the straight line would be negative.
So the interval C indicates that the function is decreasing there.
Therefore, 'linear decreasing' best describes interval C on the graph shown.
Hey there!
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Good luck on your assignment and enjoy your day!
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Since the function f(x) is written in the form y = mx + b, where m is the slope and b is the y-intercept, it currently has a y-intercept of b = 6. If this function is shifted downwards (vertically) by 12 units, its new y-intercept will be: