A.)
x y
1 1
2 4
3 9
dx=2-1→dx=1 dy=4-1→dy=3
dx=3-2→dx=1 dy=9-4→dy=5 different to 3, then this table can not be represented by a line
B.)
x y
1 2
2 5
3 10
dx=2-1→dx=1 dy=5-2→dy=3
dx=3-2→dx=1 dy=10-5→dy=5 different to 3, then this table can not be represented by a line
C.)
x y
1 3
2 6
3 9
dx=2-1→dx=1 dy=6-3→dy=3
dx=3-2→dx=1 dy=9-6→dy=3, then this table can be represented by a line
D.)
x y
1 0
2 3
3 8
dx=2-1→dx=1 dy=3-0→dy=3
dx=3-2→dx=1 dy=8-3→dy=5 different to 3, then this table can not be represented by a line
Answer: Option C. x 1 2 3 y 3 6 9
Answer:
a,c,e
Step-by-step explanation:
Answer: For this case we have the following expression:
We must factor the term that accompanies the variable.
We have then:
Rewriting the expression we have:
We're going to check the result. To do this, we multiply the term 3/8 for each term within the parenthesis:
Rewriting:
The factorization is correct.
Answer:
(3/8) (d + 2)
Hope this helps... Stay safe and have a great rest of the day... :D
Answer:
10 times
Step-by-step explanation:
Since the leftmost value is called ones place.
the second leftmost value is called tens place.
the third leftmost value is called a hundred place.
the fourth leftmost value is called a thousand place and so on.
So, The value of 4 in 4,735 is 4 thousand = 4,000
and the value of 4 in 6,412 is 4 hundred = 400.
Hence, the value of the 4 in 4,735 is 10 times the value of the 4 in 6,412.
I'm not sure, but I think it's because he didn't show the steps of him moving the X around?
