Pound is closest to a kilogram
Answer: 659 13/18 yd^2 or 659.7yd^2 ^ =squared
Step-by-step explanation:
This is the answer because you have 6 sides of this prism. That means 3 sides are parallel to the sides across from them. So, 12 1/2 yd by 8 1/3 yd is 104 1/6, then multiply by 2. That equals 208 1/3. Then, 10 5/6 yd by 8 1/3 yd is 90 5/18. then times by 2. That equals 180 5/9. Next, 10 5/6yd by 12 1/2 is 135 and 5/12. then times by 2 and that is 270 5/6yd.
add 208 1/3 + 180 5/9 + 270 5/6
659 13/18 yd^2
Answer:
14). 2nd quadrant
15). 1st quadrant
Step-by-step explanation:
14).Coordinates of a point → J(-8, -12)
Coordinates of the new point J' after reflection of x-axis will follow the rule,
(x, y) → (x, -y)
Coordinates of J' → (-8, 12)
Therefore, point J' will lie in 2nd quadrant.
15). Coordinates of a point → W(-6, 7)
Rule for the rotation by 90°clockwise about the origin,
(x, y) → (y, -x)
Coordinates of point W → (-6, 7)
Following this rule,
W(-6, 7) → W'(7, 6)
Therefore, point W' will lie in the first quadrant.
8/24 = x / 48
cross multiply
(24)(x) = (8)(48)
24x = 384
x = 384/24
x = 16 <===
Answer:
Option B. Cosec θ = –5/3
Option C. Cot θ = 4/3
Option D. Cos θ = –4/5
Step-by-step explanation:
From the question given above, the following data were obtained:
Tan θ = 3/4
θ is in 3rd quadrant
Recall
Tan θ = Opposite / Adjacent
Tan θ = 3/4 = Opposite / Adjacent
Thus,
Opposite = 3
Adjacent = 4
Next, we shall determine the Hypothenus. This can be obtained as follow:
Opposite = 3
Adjacent = 4
Hypothenus =?
Hypo² = Opp² + Adj²
Hypo² = 3² + 4²
Hypo² = 9 + 16
Hypo² = 25
Take the square root of both side
Hypo = √25
Hypothenus = 5
Recall:
In the 3rd quadant, only Tan is positive.
Therefore,
Hypothenus = –5
Finally, we shall determine Sine θ, Cos θ, Cot θ and Cosec θ to determine which option is correct. This can be obtained as follow:
Opposite = 3
Adjacent = 4
Hypothenus = –5
Sine θ = Opposite / Hypothenus
Sine θ = 3/–5
Sine θ = –3/5
Cos θ = Adjacent / Hypothenus
Cos θ = 4/–5
Cos θ = –4/5
Cot θ = 1/ Tan θ
Tan θ = 3/4
Cot θ = 1 ÷ 3/4
Invert
Cot θ = 1 × 4/3
Cot θ = 4/3
Cosec θ = 1/ Sine θ
Sine θ = –3/5
Cosec θ = 1 ÷ –3/5
Invert
Cosec θ = 1 × –5/3
Cosec θ = –5/3
SUMMARY
Sine θ = –3/5
Cos θ = –4/5
Tan θ = 3/4
Cot θ = 4/3
Cosec θ = –5/3
Therefore, option B, C and D gives the correct answer to the question.
