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Bingel [31]
3 years ago
13

How can you use two-step equations to represent and solve real-world problems?

Mathematics
2 answers:
ella [17]3 years ago
3 0
A two-step equation in a real world problem can be solved using these steps:-

- Identify the variables
- Write a equation
- Solve for the unknowns
- Answer the question and include units. 
Marat540 [252]3 years ago
3 0
Two step equations are like 8x+5=29. You could write a problem like Cara wants to rent a bike, it cost $5 and $8 per hour. How many hours did she go biking? Subtractst 5 from each side. 8x=24 Divide by 3. X=3 She biked 3 hours
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I'LL MARK BRAINLIEST JUST PLEASE HELP!!!!!
Oduvanchick [21]
The ratio of the frequency at which he picks blue is 18:32 which simplifies to 9:16 but if you want a percentage its 36%
7 0
4 years ago
arnob, bella, colin, dante, and erin are going to a baseball game. they have a total budget of $100.00 to spend. each game ticke
Alex73 [517]
87.50 + 2x < = 100 (thats less then or equal)
7 0
4 years ago
Read 2 more answers
Suppose you roll a six sided number cube one time. What is the probability of rolling a 3 or an even number
Vikki [24]
There are 3 even numbers: 2,4,6. If you add 3 there is 4. There is 6 possible outcomes 1,2,3,4,5,6. So the probability is 4/6, 2/3, 66.666....% or 0.6666666....
8 0
3 years ago
Evaluate 3/7 r + 5/8 s when r is 14 and s is 8
forsale [732]

Answer:

11

Step-by-step explanation:

Making the appropriate substitutions, we get

3/7 r + 5/8 s  =>  3/7 (14) + 5/8 (8).

Notice how this can reduced:

                             3(14)            5(8)

                           ----------- +     ---------   =   6 + 5 = 11

                                  7                8

6 0
3 years ago
A patient with high blood pressure who weighs 226 pounds is put on a diet to lose 26 pounds in 3 months. The patient loses 8 3 4
dimaraw [331]

Given :

A patient with high blood pressure who weighs 226 pounds is put on a diet to lose 26 pounds in 3 months. The patient loses 8 3/4 pounds the first month and 11 5/8 pounds the second month.

To Find :

How much weight must be lost the third month for the goal to be achieved.

Solution :

Let, weight lose in third month is x.

So, 8 3/4 + 11 5/8 + x = 26

\dfrac{32+3}{4}+\dfrac{88+5}{8}+x=26\\\\x = 26 - ( \dfrac{35}{4}+\dfrac{93}{8})\\\\x=5.625\ pounds

Therefore, weight lose in third month is 5.625 pounds.

Hence, this is the required solution.

3 0
3 years ago
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