Solve the proportions, round your answers to 1 decimal digit. <br> 24/66 = 9/x

2a + 1 > 9 or a < –1

SVEN [57.7K]

Answer:

I don't know what you mean, but I'll say 2a+1>9 is a>4

Step-by-step explanation:

7 0

3 years ago

40% of the students passed both exams. 80% of the students passed the second exam. how many students (in percent) who passed the

navik [9.2K]

50%. students (in percent) who passed the second exam also passed the first exam.

Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.

Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.

Thus, both tests were passed by 40 of the 80 pupils who passed the second one:

40/80 = 1/2 = 50%.

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7 0

1 year ago

What is the area of the shaded triangle inside the square? Round your answer to the nearest square inch.

EastWind [94]

Answer:

128 inches squared

Step-by-step explanation:

7 0

3 years ago

How do similar triangles work?

Keith_Richards [23]

Explanation:

Triangles are similar when their corresponding angles are identical in measure, and their corresponding sides are proportional.

Problems involving similar triangles make use of these characteristics.*

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Triangles are named by naming their vertices, such as ΔABC, for example. If another triangle is similar, that fact is indicated using the wavy-line similarity symbol (~) between their names. For example:

ΔABC ~ ΔPQR

Corresponding angles are ones in the same position in the triangle's name. For example, angles B and Q correspond, because they are both named second in the similarity statement.

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Corresponding sides are named by using corresponding vertex names. For example, sides CA and RP are corresponding, because they are both named using the 3rd and 1st letters of the triangle names in the similarity statement.

Corresponding sides are proportional. This can be written different ways. Here are a couple of them:

AB : BC : CA = PQ : QR : RP

AB : PQ = BC : QR = CA : RP . . . . ratios are the same; they may be > 1 or < 1.

This means that if you know the ratio of any two corresponding sides in similar triangles, you know the ratio of all corresponding sides. This fact is used to solve problems involving side lengths.

Typically you might be given two sides of one triangle and two sides of a similar triangle (one corresponding). You can find the measures of the two missing sides by making use of the above relationships.

_____

* In general, problems in algebra and geometry make use of the relationships you learn. That is the point of learning the relationships. They let you write equations that relate what you know to what you don't know. Solving these equations lets you solve the problem.

7 0

4 years ago

Jim saw that other bank offered the same rates but compounded the interest more often. Consider if he still put $15,000 into a s

Kazeer [188]

Compound interest is the addition of interest on the interest of the principal amount.

<h3>What is compound interest?</h3>

Compound interest is the addition of interest on the interest of the principal amount. It is given by the formula,

$A = P(1+ \dfrac{r}{n})^{nt}$

As it is given that the principal amount is $15,000; while the rate of interest is 2.8%, and the amount is invested for a period of 5 years.

A.) When the interest is charged weekly,

As we know that there are 52 weeks in a year, therefore, n = 52, substitute the values,

$A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{52})^{52 \times 5}\\\\A = \$17,253.46$

B.) When the interest is charged daily,

As we know that there are 365 days in a year, therefore, n = 365, substitute the values,

$A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{365})^{365 \times 5}\\\\A = \$19,554.55$

C.) When the interest is charged Continuously,

As we know that the formula for continuous compounding is given as,

$A = Pe^{rt}$

Substitute the values, we will get,

$A = 15000 \times (e^{0.024 \times 5})\\\\A= \$16,912.45$

D.) When the interest is charged Monthly,

As we know that there are 12 months in a year, therefore, n = 12, substitute the values,

$A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{12})^{12\times 5}\\\\A = \$15211.23$

E.) When the interest is charged Semi-annually,

As we know that the interest is charged Semi-annually, therefore, n = 2, substitute the values,

$A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{2})^{2\times 5}\\\\A = \$17,237.36$

F.) When the interest is charged Quarterly,

As we know that the interest is charged Quarterly, therefore, n = 4, substitute the values,

$A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{4})^{4\times 5}\\\\A = \$17,245.7$

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4 0

3 years ago

Read 2 more answers

Solve the proportions, round your answers to 1 decimal digit. 24/66 = 9/x