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Amanda [17]
3 years ago
15

(WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST) Directed line segment is graphed below. Plot point R on the graph so that it spl

its into segments with a ratio of 1:2.
Explain how you determined your answer

Mathematics
1 answer:
guajiro [1.7K]3 years ago
4 0

Answer:

(0 , -1)

Step-by-step explanation:

WR = 4 + 2 = 6

WS = 1/3 x WR = 2   .... the point of 1:2 of WR

S (-2 + 2 , -4) i.e. (0,4)

The same reason: RQ = 1/3 x RY = 1/3 x (5 + 4) = 3

Q (-4 , -4 + 3) i.e. (-4, -1)

QP // RW

p (0 , -1)

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If someone can give me the answers for all :)
tia_tia [17]

Answer:

1. x²=a² + b²

x²=10²+7²

x²=100+49

x²=149

x=√149

12.206555615

x=12.2

2.x²= a²+b²

x²=19²+ 21²

x²=361+441

x²=802

x=√802

x=28.319604517

x=28.3

3.x²=a²+b²

x²=27²+16²

x²=729+256

x²=985

x=√985

x=31.384709652

x=31.3

4.x²=a²+b²

x²= 163.84+ 28.109

x²=191.93

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4 0
3 years ago
How to divide and simplify this radical expression
Evgen [1.6K]

Answer:

  \dfrac{2x}{5}\sqrt[3]{50x^2}

Step-by-step explanation:

Since the root indices are the same, the fraction can be combined under one radical. Then you want to do two things:

  • factor out perfect cubes
  • make the denominator a perfect cube (so it can be factored out)

__

  \displaystyle\dfrac{\sqrt[3]{16x^8y^2}}{\sqrt[3]{5x^3y^2}}=\sqrt[3]{\dfrac{16x^8y^2}{5x^3y^2}}=\sqrt[3]{\dfrac{16x^5}{5}}=\sqrt[3]{\dfrac{(2x)^3\cdot2\cdot5^2x^2}{5^3}}\\\\=\boxed{\dfrac{2x}{5}\sqrt[3]{50x^2}}

8 0
2 years ago
Solve each equation. Show your work please. Part 2​
ki77a [65]

Answer:

4) x=2.52 (3 s.f.)

5) x= -43

6) x= -184

Step-by-step explanation:

Please see attached picture for full solution.

6 0
3 years ago
Tell me step-by-step how to convert 0.15 repeating 15 to a fraction
Ulleksa [173]

Answer:

7/45

Step-by-step explanation:

If you can use your calculator*

Just press 0.1555555555555555555555555555 repeatedly

If you cant:

I dont know sorry

4 0
3 years ago
Suppose you have a cube of length s. The volume of that cube is V = s^3. Now let's suppose the dimensions of that cube (and henc
Grace [21]

Answer:

Part 1

s'(t)=1

V'(t)=3t^2

Part 2

s'(t)=\frac{1}{3\sqrt[3]{t^2}}

V'(t)=1

Step-by-step explanation:

As stated in the question, if s is the length of a cube, its volume is

V(s)=s^3

When s changes in time, the volume will change too. The challenge here is to find the growth of the volume in terms of those changes in length

Part 1

s(t)=t

The change of s with respect to time is found by differentiating the relation to get

s'=1

The volume will also change, and its derivative is

V'(s)=3s^2.s'

Since s'=1

V'(s)=3s^2

How s=t

V'(t)=3t^2

Part 2

V(t)=t

Replacing this into the formula for V(s)

V(s)=s^3=t

So we have

s=\sqrt[3]{t}=t^{\frac{1}{3}}

Computing the derivatives:

V(t)=t =>

V'(t)=1

s'(t)=\frac{1}{3}t^{-\frac{2}{3}}=\frac{1}{3\sqrt[3]{t^2}}

7 0
3 years ago
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