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Brilliant_brown [7]
4 years ago
9

Thx for helping if u do

Mathematics
1 answer:
Helen [10]4 years ago
7 0
6 : 10 = 3 : 5
24 : 40 = 3 : 5
36 : 60 = 3 : 5
42 : 70 = 3 : 5

A. 18 : 20 = 9 : 10 (incorrect)
B. 30 : 20 = 3 : 2 (incorrect)
C. 18 : 30 = 3 : 5 (correct)
D. 50 : 30 = 5 : 3 (incorrect)

The answer is C. 18 : 30

Hope this helps. - M
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169= (24/2)^2 +(d/2)^2
OlgaM077 [116]

Answer: d = ±10

<u>Step-by-step explanation:</u>

169 = (\frac{24}{2})^{2} + (\frac{d}{2})^{2}

169 = (12)² + \frac{d^{2}}{4}

169 = 144  + \frac{d^{2}}{4}

25 =            \frac{d^{2}}{4}

100 = d²

√100 = √d²

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Which figure has exacly 2 sets of parallel sides and no perpendicular sides
sweet-ann [11.9K]
Square. Because there is 2 right angles there are only 4 sides all which are perpendicular
5 0
3 years ago
If sinA =3/5 and A+B =90 find cosB
-Dominant- [34]

A+B=90^o\to B=90^o-A\\\\\cos B=\cos(90^o-A)=\cos90^o\cos A+\sin90^o\sin A\\\\=\cos A+1\cdot\dfrac{3}{5}=0+\dfrac{3}{5}=\dfrac{3}{5}\\\\\boxed{\cos B=\dfrac{3}{5}}

Used:\\\\\cos(x+y)=\cos x\cos y+\sin x\sin y\\\\\cos90^o=0,\ sin90^o=1

Other method:

Look at the picture.

\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\sin A=\dfrac{3}{5}\to opposite=3\ and\ hypotenuse=5

\cos\theta=\dfrac{adjacent}{hypotenuse}\\\\adjacent=3\ and\ hypotenuse=5\to\cos B=\dfrac{3}{5}

8 0
3 years ago
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Hitman42 [59]
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