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rewona [7]
2 years ago
8

Find the total area of the composite figure below. SHOW ALL WORK.

Mathematics
1 answer:
Leviafan [203]2 years ago
5 0

Answer:

358.5 sq-in

Step-by-step explanation:

This is the answer.

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Write the numbers in order from least to greatest. 0.3.0.5.-1.6.-1.35​
Tju [1.3M]
-1.6
-1.35
0.3
0.5
Top to bottom, top is the lowest
4 0
2 years ago
LAST QUESTION! 12 Points! Will mark brainliest! Links will be ignored and deleted.
insens350 [35]

Answer:

i belive its 35/8 3.14

Step-by-step explanation:

sorry if im wrong

4 0
3 years ago
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One third of the sum of a number and four
STatiana [176]

Answer:

\frac{1}{3} (n+4)

That is what the expression would be

4 0
3 years ago
Taxi A charges a fee of $3.50, plus $1.75 per mile. Taxi B charges a few of $1.25, plus $2.00 per mile. At what distance would t
frez [133]
Taxi A
1mile £3.50+£1.75=£5.25
Taxi B
1mile £1.25+£2.00=£3.25

Taxi A
2miles £3.50+£3.50=£7.00
Taxi B
2miles £1.25+£4.00=£5.25

Taxi A
3miles £3.50+£5.25=£8.75
Taxi B
3miles £1.25+£6.00=£7.25

Taxi A
4miles £3.50+£7.00=£10.50
Taxi B
4miles £1.25+£8.00=£9.25

Taxi A
5miles £3.50+£8.75=£12.25
Taxi B
5miles £1.25+£10.00=£11.25

Taxi A
6miles £3.50+£10.50=£14.00
Taxi B
6miles £1.25+£12.00=£13.25

Taxi A
7miles £3.50+£12.25=£15.75
Taxi B
7miles £1.25+£14.00=£15.25

Taxi A
8miles £3.50+£14.00=£17.50
Taxi B
8miles £1.25+£16.00=£17.25

Taxi A
9miles £3.50+£15.75=£19.25 (the same)
Taxi B
9miles £1.25+£18.00=£19.25 (the same)

^^^
They would have to drive 9 miles for the taxi to cost the same.

Hope this helped, this is the longest way to work it out but also the simplest.
6 0
2 years ago
In a random sample of 200 Americans, 51% said they favor building more nuclear power plants. In a random sample of 150 French, 4
Varvara68 [4.7K]

Answer:

Yes, there is enough evidence to say the proportions are the same.

Step-by-step explanation:

Null hypothesis: The proportions are the same.

Alternate hypothesis: The proportions are not the same.

Data given:

p1 = 51% = 0.51

n1 = 200

p2 = 48% = 0.48

n2 = 150

pooled proportion (p) = (n1p1 + n2p2) ÷ (n1 + n2) = (200×0.51 + 150×0.48) ÷ (200 + 150) = 174 ÷ 350 = 0.497

Test statistic (z) = (p1 - p2) ÷ sqrt[p(1-p)(1/n1 + 1/n2) = (0.51 - 0.48) ÷ sqrt[0.497(1-0.497)(1/200 + 1/150)] = 0.03 ÷ 0.054 = 0.556

The test is a two-tailed test. At 0.10 significance level the critical values -1.645 and 1.645

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.556 falls within the region bounded by the critical values.

8 0
3 years ago
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